/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Q. 31 Use the Maclaurin series for 11-... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

Use the Maclaurin series for 11-xto find power series representations for 11+x, ln(1+x), ∫ln(1+x)dx , and∫02ln(1+x)dx.

Short Answer

Expert verified

The power series are

11+x=1-x+x2-x3+x4ln(1+x)=x-x22+x33-x44+x55-...∫ln(1+x)=x22-x36+x412-x520+x630-....∫02ln(1+x)dx=222-236+2412-2520+2630-....

Step by step solution

01

Given information

We are given a power series of11-x

02

Find the power series of 11+x

The power series of 11-xcan be given as

11-x=1+x+x2+x3+x4+.....

Replacing x by -x we get,

11+x=1-x+x2-x3+x4-.....

03

Find the power series of ln(1+x)

We have find the power series of 11+xwhich is

11+x=1-x+x2-x3+x4-....

On integrating we get,

ln(1+x)=x-x22+x33-x44+x55-....

Again integrating the power series we get,

∫ln(1+x)=x22-x36+x412-x520+x630-...

And finally on integrating within the limits

role="math" localid="1654231180835" ∫02ln(1+x)dx=[x22-x36+x412-x520+x630-..]20∫02ln(1+x)dx=[2-86+1612-3220+6430-...

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Study anywhere. Anytime. Across all devices.