/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Q 69. Use your result from Exercise 68... [FREE SOLUTION] | 91Ó°ÊÓ

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Use your result from Exercise 68 to show that the arc length formula for a function y=f(x) is a special case of the arc length formula for a parametric curve.

Short Answer

Expert verified

∫ab1+f'(t)2dt

Step by step solution

01

Given information

y=f(x)

02

Calculation

Consider the function y=f(x)

For a parameter tthe function y=f(t)for some t∈[a,b]

The goal is to determine the curve's arc length.

If the curve Cis expressed by parametric equations x=f(t),y=y(t)on the interval [a,b]then the arc length is given by the formula,

∫abf'(t)2+g'(t)2dt

Thus, f(t)=x⇒f'(t)=dxdt

g(t)=y⇒g'(t)=dydt

Substituting the values of f'(t),g'(t)then the arc length is

Arc length =∫abddtx2+ddty2dt

=∫abdxdt2+dydt2dt

Then,

Arc length =∫ab1+dydt2dt

Arc length =∫ab1+f'(t)2dt[since , for some parameter t]Therefore the arc length of the curve y=f(t)is ∫ab1+f'(t)2dt

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