Q. 63 . Prove that the graph of the eq... [FREE SOLUTION]

Chapter 9: Q. 63 (page 732)

. Prove that the graph of the equation $r = k c o e s c 胃$ , $0 < 胃 < 蟺$ , is a horizontal line for any value of $k 鈮� 0$

Short Answer

Expert verified

Equation in rectangular form is $y = k$ , hence it represent a horizontal line which is at a distance of $k$ units from $x -$ axis.

Step by step solution

Step 1. Given information

The equation in polar form : $r = k \cos e c 胃$

$0 < 胃 < 蟺$

Step 2. Convert the polar form of equation into rectangular form:

Since in $y = r \sin 胃$

$\sin 胃 = \frac{y}{r} \cos e c 胃 = \frac{r}{y}$

$r = k \cos e c 胃 r = k (\frac{r}{y}) y = k$

This is an equation of horizontal line .

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91影视

. Prove that the graph of the equation $r = k c o e s c 胃$ , $0 < 胃 < 蟺$ , is a horizontal line for any value of $k 鈮� 0$

Short Answer

Step by step solution

Step 1. Given information

Step 2. Convert the polar form of equation into rectangular form:

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91影视

. Prove that the graph of the equation r=kcoesc胃, 0<胃<蟺, is a horizontal line for any value of k鈮�0

Short Answer

Step by step solution

Step 1. Given information

Step 2. Convert the polar form of equation into rectangular form:

One App. One Place for Learning.

Most popular questions from this chapter

Recommended explanations on Math Textbooks

Pure Maths

Theoretical and Mathematical Physics

Probability and Statistics

Decision Maths

Discrete Mathematics

Calculus

Study anywhere. Anytime. Across all devices.

. Prove that the graph of the equation $r = k c o e s c 胃$ , $0 < 胃 < 蟺$ , is a horizontal line for any value of $k 鈮� 0$