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Determine the domains of the functions in Exercises 47–56, and find where the functions are continuous.

f(x,y)=x2x2-y2

Short Answer

Expert verified

The function f(x,y)=x2x2-y2is continuous on the set x,y∈f2:x2≠y2.

Step by step solution

01

Step 1. Given information.  

We have given expression: f(x,y)=x2x2-y2

02

Determine the domains of the functions.

Consider the function:g:f2→f. Then the domain of the function is

Domaing=x,y∈f2:g(x,y)isdefined

Since the rational function f(x,y)=x2x2-y2is defined for all x,y∈f2such that

x2-y2≠0x2≠y2

The domain of the function isrole="math" localid="1653241952198" Domain(f)=x,y∈f2:x2≠y2
.

03

Step 3. To find continuous of the function.

Since x2and x2-y2being a polynomial function of two variable is continuous for every point on f2.

The rational function is continuous where all those points where x2x2-y2is defined.

The rational function is discontinuous only at the points wherex2-y2=0that is x=y.

Hence the given function f(x,y)=x2x2-y2is continuous on the setx,y∈f2:x2≠y2.

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