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Find functions f and g and a real number c such that limx→cf(x)+limx→cg(x)≠limx→c(f(x)+g(x)). Does this example contradict the sum rule for limits? Why or why not?

Short Answer

Expert verified

The functions f(x)=1xand g(x)=-1xand a real number c=0such that limx→cf(x)+limx→cg(x)≠limx→c(f(x)+g(x))andcontradict the sum rule for limits.

Step by step solution

01

Step 1. Given information.

Given a conditionlimx→cf(x)+limx→cg(x)≠limx→c(f(x)+g(x)).

02

Step 2. Example for the given condition.

Let f(x)=1xand g(x)=-1xand a real number c=0such that limit is x→0.

We have

limx→0(f(x)+g(x))=limx→0(1x+(-1x))=limx→0(1x-1x)=limx→0(0)=0

and

limx→0f(x)+limx→0g(x)=limx→01x+limx→0(-1x)=limx→010-limx→010=undefined

So limx→cf(x)+limx→cg(x)≠limx→c(f(x)+g(x))and given example contradict the sum rule for limits, which stateslimx→cf(x)+limx→cg(x)=limx→c(f(x)+g(x))

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