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Write delta-epsilon proofs for each of the limit statements in Exercises 47–60.

limx→2x2-3x+2x-2=1

Short Answer

Expert verified

Delta-epsilon proof is,

Whenever 0<|x-2|<δ, we also have x2-3x+2x-2-1<ϵ.

Step by step solution

01

Step 1. Given information  

We are given,

limx→2x2-3x+2x-2=1

02

Step 2. Writing the delta-epsilon proofs 

The strategy is to write delta-epsilon proofs for the given limit statement.

Consider that ∈>0, choose δ=ϵ.

For all x with 0<|x-2|<δ, we also have x2-3x+2x-2-1<ϵ.

x2-3x+2x-2-1=x2-3x+2-1(x-2)x-2=x2-3x+2-x+2x-2=x2-4x+4x-2=(x-2)2x-2=|x-2|<δ=∈

So, whenever 0<|x-2|<δ, we also have x2-3x+2x-2-1<ϵ.

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