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Chapter 1: Q. 48 (page 136)

limx鈫�+22x-4

Short Answer

Expert verified

limx鈫�+22x-4=0

Step by step solution

01

Step 1. Given information

limx鈫�+22x-4

02

Step 2. Plug in the values

limx鈫�+22x-4=22-4

limx鈫�+22x-4=4-4

limx鈫�+22x-4=0

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Most popular questions from this chapter

For each limit statement , use algebra to find 未 > 0 in terms of 蔚> 0 so that if 0 < |x 鈭� c| < 未, then | f(x) 鈭� L| < 蔚.

limx鈫�0(x3+1)=1

In Exercises 39鈥�44, use Theorem 1.16 and left and right limits to determine whether each function f is continuous at its break point(s). For each discontinuity of f, describe the type of discontinuity and any one-sided discontinuity.

f(x)=(x-3),ifx<0-(x-3),ifx猢�0.

Write a delta鈥揺psilon proof that proves that fis continuous on its domain. In each case, you will need to assume that 未 is less than or equal to 1.

f(x)=x鈭�1/2

For each limit in Exercises 33鈥�38, either use continuity to calculate the limit or explain why Theorem 1.16 does not apply.

limx鈫�-1x.

Each function in Exercises 9鈥�12 is discontinuous at some value x = c. Describe the type of discontinuity and any one-sided continuity at x = c, and sketch a possible graph of f.

limx鈫�-1-f(x)=2,limx鈫�-1+f(x)=2,f(-1)=1.
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