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In Exercises 39–44, use Theorem 1.16 and left and right limits to determine whether each function f is continuous at its break point(s). For each discontinuity of f, describe the type of discontinuity and any one-sided discontinuity.

f(x)=(x-3),ifx<0-(x-3),ifx⩾0.

Short Answer

Expert verified

Thegivenfunctionisnotcontinuousatx=0,ithasjumpdiscontinuityanditisrightcontinuous.

Step by step solution

01

Step 1. Given Information. 

Given the function;

f(x)=(x-3),ifx<0-(x-3),ifx⩾0andithasit'sbreakpointatx=0.

02

Step 2. Finding the limits at the break point.

Atx=0,LHL=limx→0-f(x)=limx→0-(x-3)=0-3=-3.RHL=limx→0+f(x)=limx→0+-(x-3)=-(0-3)=3.f(0)=-(x-3)=-(0-3)=3.So,RHL=f(0)≠LHL.

03

Step 3. Finding the type of discontinuity. 

Since the function is discontinuous only at x=0,from Step 2.

Now we know LHL≠RHLthis means both left and righthand limit exists but they are not equal so this is jump discontinuity.

And also, RHL = f(0) this means this function is right continuous.

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