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91Ó°ÊÓ

Determine whether each function approaches 0, approaches a nonzero real number, or becomes infinite as x approaches each indicated value.

f(x)=cscx,withx→0andx→π.f(x)=tan2x,withx→0andx→π.f(x)=sin-1x,withx→0andx→1.f(x)=tan-1x,withx→0andx→3.

Short Answer

Expert verified

Function f(x)=cscxapproaches ∞as x→0and x→π.

Function f(x)=tan2xapproaches 0as x→0andx→π.

Function f(x)=sin-1xapproaches 0as x→0and approaches π2asx→1.

Function f(x)=tan-1xapproaches 0as x→0and approaches π3asx→3.

Step by step solution

01

Step 1. Given information.

Given functions with limits are the following.
f(x)=cscx,withx→0andx→π.f(x)=tan2x,withx→0andx→π.f(x)=sin-1x,withx→0andx→1.f(x)=tan-1x,withx→0andx→3.

02

Step 2. Limits of the first function.

Take function f(x)=cscx.

Check the function as x→0.

limx→0cscx=∞

Check the function asx→π.

limx→πcscx=∞

03

Step 3. Limits of the second function.

Take functionf(x)=tan2x.

Check the function asx→0.

role="math" localid="1648721836526" limx→0tan2x=0

Check the function as x→π.

limx→πtan2x=0

04

Step 4. Limits of the third function.

Take functionf(x)=sin-1x.

Check the function asx→0.

limx→0f(x)=limx→0sin-1xlimx→0f(x)=0

Check the function as x→1.

limx→1f(x)=limx→0sin-1xlimx→1f(x)=π2

05

Step 5. Limits of the fourth function.

Take functionf(x)=tan-1x.

Check the function asx→0.

limx→0f(x)=limx→0tan-1xlimx→0f(x)=0

Check the function as x→3.

limx→3f(x)=limx→0tan-1xlimx→3f(x)=π3.

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