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Each of the integrals or integral expressions in Exercises 39-46 represents the volume of a solid in 3. Use polar coordinates to describe the solid, and evaluate the expressions.

h020Rr-r2Rdrd

Short Answer

Expert verified

The value of integral is

h020Rr-r2Rdrd=hR23

Step by step solution

01

Given information

The expression isI=h020Rr-r2Rdrd

02

Calculation

Here, r=0,r=Rand =0,=2

Integrate with respect to r first,

I=h02r22-r33R0Rdxndx=xn+1n+1+C

Put the limits

I=h02R22-R33Rd

localid="1651390798747" I=h02R26d

Now integrate with respect to

I=hR26[]02I=hR26[2]

I=hR23

Thus, the value of integral is

localid="1651390833501" h020Rr-r2Rdrd=hR23

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