/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Q. 29 Use Definition 13.4聽to evaluate... [FREE SOLUTION] | 91影视

91影视

Use Definition 13.4to evaluate the double integrals in Exercises 2932.

RxydA

where

R={(x,y)0x2&1y4}

Short Answer

Expert verified

The value of integral is15

Step by step solution

01

Step 1. Given information

An integral is given asRxydA

02

Step 2. Evaluating integral

By definition the double integration is

Rf(x,y)dA=lim0j=1mk=1nfxj*,yk*A=lim0k=1nj=1mfxj*,yk*A

where

xj=a+jxyk=b+kyA=xyx=b-amy=d-cn

The starred points xj*,yk*lets choose xj,yk=(0+jx,1+ky)=(jx,1+ky) for each jand k

Rf(x,y)dA=lim0j=1mk=1n(jx)(1+ky)Aj=1mk=1n(jx)(1+ky)A=j=1m(jx)Ak=1n(1+ky)=j=1m(jx)Ak=1n1+k=1nky=j=1m(jx)An+yn(n+1)2=n+yn(n+1)2Aj=1m(jx)=n+yn(n+1)2Axj=1m(j)=n+yn(n+1)2xm(m+1)2A

Recall,

x=b-am=2-0m=2my=d-cn=4-1n=3nA=xy=2m3n=6mnj=1mk=1n(jx)(1+ky)A=n+yn(n+1)2xm(m+1)2A=n+3nn(n+1)22mm(m+1)26mn=6n1n+3n1nn(n+1)21m2mm(m+1)2=61+32(n+1)n(m+1)m

The double integration is

Rf(x,y)dA=lim0j=1mk=1n(jx)(1+ky)A=lim061+32(n+1)n(m+1)m=limmlimn61+32(n+1)n(m+1)m=6limmlimn1+32(n+1)n(m+1)m=6limmlimn1+limn32(n+1)n(m+1)m=6limm1+32(m+1)m=61+32limm(m+1)m=652(1)=15

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91影视!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Study anywhere. Anytime. Across all devices.