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Use definition to evaluate the double integral

Rx2y3dAWhereR={(x,y)|1x3,0y2}

Short Answer

Expert verified

The value of the integral is 126

Step by step solution

01

Given information

We are given a double integral

Rx2y3dAWhereR={(x,y)|1x3,0y2}

02

Use definition to find the value of double integral

We get,

i=02x2y3j=13=i=02(y3+4y3+9y3)=i=02(14y3)=14(1)+14(8)=126

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