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Let [a1,a2],[b1,b2],[c1,c2]be three closed intervals explain why the triple integral ∫a1a2∫b1b2∫c1c2dzdydxcomputes the volume of the rectangular solid with lengtha2-a1, widthb2-b1 and heightc2-c1

Short Answer

Expert verified

On evaluating the triple integral we get a value which is equal to the volume of the rectangular box with given length width and height

Step by step solution

01

Given information 

We are given a triple integral∫a1a2∫b1b2∫c1c2dzdydx

02

Explaination

On evaluating the triple integral we get,

∫a1a2∫b1b2∫c1c2dzdydx=∫a1a2∫b1b2[c2-c1]dydx=∫a1a2[b2-b1][c2-c1]dx=[a2-a1][b2-b1][c2-c1]

We know the volume of a rectangular region with length width and height is lwh. Hence this integral represents the volume of the rectangular region with length width and height[a2-a1][b2-b1][c2-c1] respectively

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