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Each of the integral expressions that follow represents the area of a region in the plane bounded by a function expressed in polar coordinates. Use the ideas from this section and from Chapter 9 to sketch the regions, and then evaluate each integral

120cos23d

Short Answer

Expert verified

The area is4square units.

Step by step solution

01

Step 1. Given information

Integral:

120cos23d
02

Step 2. Plot the curve

Since the area of a function r=f()is 120r2d

So by comparing the given integral we get,

r=cos3

So the graph of this curve is:

03

Step 3. Evaluate integral

120cos23d=120cos23d=1201+cos62d=1401+cos6d=14+sin660=14+sin66-0=4

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