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In Exercises 72–77, find a function f that has the given derivative f. In each case you can find the answer with an educated guess-and-check process. (Some of these exercises involve hyperbolic functions.)

f'(x)=19-x2

Short Answer

Expert verified

The function that has the derivative f'(x)=19-x2is f(x)=13tanh-1(x3).

Step by step solution

01

Step 1. Given Information.

The derivative:

f'(x)=19-x2

02

Step 2. Guess the formula for the given derivative.

We know that,

ddx(tanh-1x)=11-x2

So we can conclude that the derivative will be of the form of hyperbolic sinefunction.

03

Step 3. Check guess-and-check process.

Consider the function,

f(x)=tanh-1(x3)f'(x)=11-(x3)2.13=13(1-x29)=1(9-x23)=39-x2

which is not a given derivative.

04

Step 4. Check another function. 

Consider the function,

f(x)=13tanh-1(x3)f'(x)=13(11-(x3)2.13)=13(13(1-x29))=13(1(9-x23))=13(39-x2)=11-9x2

which is the given derivative.

So the function isf(x)=13tanh-1(x3).

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