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91Ó°ÊÓ

Use the definition of the derivative to find the equations of the lines described in Exercises 59-64.

The line that is perpendicular to the tangent line to f(x)=x4+1at x=2 and also passes through the point(-1,8)

Short Answer

Expert verified

The equation isy=-132x+25532

Step by step solution

01

Step 1. Given information

Given the functionf(x)=x4+1and the point(-1,8)

02

Calculate f'(2) using definition of derivative

Calculating, we get

f'(2)=limx→2f(x)-f(2)x-2f'(2)=limx→2x4+1-24+1x-2f'(2)=limx→2x4-24x-2f'(2)=limx→2(x-2)(x+2)x2+22(x-2)f'(2)=limx→2(x+2)x2+22f'(2)=(2+2)22+22f'(2)=32

03

Use point slope form and calculate the form

Calculating, we get

Line is perpendicular to tangent line so m=-132

y-8=-132(x+1)y=-132x-132+8y=-132x+25532

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