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Use the definition of the derivative to find the derivatives described in Exercises 55-58.

Findddx2x3,d2dx22x3,d3dx32x3

Short Answer

Expert verified

The derivatives are6x2,12x,12respectively

Step by step solution

01

Step 1. Given information

Given functiony=2x3

02

Use the definition of derivative and calculate

Calculating, we get

limh→0f(x+h)-f(x)h=limh→02(x+h)3-2x3hlimh→0f(x+h)-f(x)h==limh→02x3+h3+3x2h+3xh2-2x3h==limh→02x3+2h3+6x2h+6xh2-2x3h=limh→02h3+6x2h+6xh2h=limh→0h2h2+6x2+6xhh=limh→02h2+6x2+6xh=2(0)2+6x2+6x(0)=6x2ddx2x3=6x2

03

Calculating the other derivatives

Calculating, we get

limh→0g(x+h)-g(x)h=limh→06(x+h)2-6x2hlimh→0g(x+h)-g(x)h=limh→06x2+h2+2xh-6x2h=limh→06x2+6h2+12xh-6x2h=limh→06h2+12xhh=limh→0(6h+12x)=12xd2dx22x3=12x

04

Calculating the other derivatives

Calculating, we get

limh→0m(x+h)-m(x)h=limh→012(x+h)-12xhlimh→0m(x+h)-m(x)h=limh→012x+12h-12xh=limh→012hh=limh→012=12d3dx32x3=12

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