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Chapter 2: Q 22 (page 238)

: Find the derivatives of the function

sin2x+cos2xcscx

Short Answer

Expert verified

dydx=cosx

Step by step solution

01

Step 1:Given information

The given expression issin2x+cos2xcscx

02

Step 2:Simplification

y=sin2x+cos2xcscx

=1cscx鈭�sin2x+cos2x=1

=sinx

Now y=sinx

Differeniating w.r.t x

dydx=ddxsinx

鈬�dydx=cosx

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