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Use the definition of the derivative to find f'for each function fin Exercises 34-59

f(x)=1x2

Short Answer

Expert verified

The value off'(x)=-2x3

Step by step solution

01

Step 1. Given  information

The given functionf(x)=1x2

02

Step 2. Finding the value of f'(x)

We know that f'(x)=limh→0f(x+h)-f(x)h.........(1)

Given f(x)=1x2the

Putting the values in (1)

localid="1648748944158" role="math" f'(x)=limh→01(x+h)2-1x2h=limh→0x2-(x+h)2x2(x+h)2h=limh→0x2-x2-h2-2xhx2(x+h)2h=limh→0-h2-2xhx2(x+h)2h=limh→0h(-h-2x)x2(x+h)2h=limh→0h(-h-2x)x2(x+h)2×1h=limh→0(-h-2x)x2(x+h)2

Putting h=0

=-(0)-2xx2.(x+0)2=-2xx2.x2=-2x3

Hence,the value off'(x)=-2x3

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