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The given sum approximates the area between the graph of some function f and the x-axis from x = a to x = b. Do some 鈥渞everse engineering鈥 to determine the type of approximation (left sum, midpoint sum, etc.) and identify f(x), a, b, n, x, and xk. Then sketch the approximation described.

k=02ln2+k313

Short Answer

Expert verified

f(x)=x(x-1)N=4x=12xk=1+k3a=1b=3

Step by step solution

01

Step 1. Given information

Sum isk=02ln2+k313

02

Step 2. Explanation

Consider the sum k=02ln2+k313

k=02ln2+k313=ln2+0313+ln2+1313+ln2+2313

width="98">f(x)=x(x-1)N=4x=12xk=1+k3

Therefore,

a=1b=3

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