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91Ó°ÊÓ

Calculate the exact value of each definite integral in Exercises 47–52 by using properties of definite integrals and the formulas in Theorem 4.13.

∫613(1-2x)2+4xdx

Short Answer

Expert verified

The exact value of definite integral is -735.

Step by step solution

01

Step 1. Given Information  

We are given,

∫613(1-2x)2+4xdx

02

Step 2. Finding the Integral  

The definite integral is given by,

∫613(1-2x)2+4xdx=∫6131-4x+4x2+4xdx=∫613-12x+12x2+4xdx=3∫611dx-8∫61xdx+12∫61x2dx=3[1-6]-812(1-36)+1213(1-216)=-15-4(-35)+4(-215)=-15+140-860=-735

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