/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Q. 17 Show by exhibiting a counterexam... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

Show by exhibiting a counterexample that, in general, ∫f(x)g(x)dx≠∫f(x)dx∫g(x)dx. In other words, find two functions f and g so that the integral of their product is not equal to the product of their integrals.

Short Answer

Expert verified

The counterexample isf(x)=x;g(x)=1x.

Step by step solution

01

Step 1. Given information.

The given inequality is∫f(x)g(x)dx≠∫f(x)dx∫g(x)dx.

02

Step 2. Conclusion.

Let the two functions be,

f(x)=x;g(x)=1x

Now,

∫f(x)g(x)dx=∫x1xdx=x+C∫f(x)dx∫g(x)dx==∫xdx∫1xdx=x22+Clnx+C'Therefore,∫f(x)g(x)dx≠∫f(x)dx∫g(x)dx

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Study anywhere. Anytime. Across all devices.