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Use the first derivative test to determine the local extrema of each function in Exercises 39- 50. Then verify your algebraic answers with graphs from a calculator or graphing utility.f(x)=ex(x2-x-1)

Short Answer

Expert verified

Ans: The local maximum of the function f(x) isx=-2

The local minimum of the function f(x) isx=1

Step by step solution

01

Step 1. Given Information:

f(x)=ex(x2-x-1)

02

Step 2. Finding the derivative of the function:

f(x)=ex(x2-x-1)f'(x)=ex(2x-1)+(x2-x-1)exf'(x)=ex(2x-1+x2-x-1)f'(x)=ex(x2+x-2)let,f'(x)=0∴ex(x2+x-2)=0x2+x-2=0x2+2x-x-2=0x(x+2)-(x+2)=0(x+2)(x-1)=0x=-2,1thecriticalpointsarex=-2,1

03

Step 3. Substituting the values into the function equation:

f(-2)=e(-2)((-2)2-(-2)-1)=e-2(4+2-1)=5e-2f(1)=e(1)((1)2-(1)-1)=-e∴thelocalmaximumatx=-2;andthelocalmimimumatx=1

04

Step 4. Verifying algebraic answers with graphs : 

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