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Use a sign chart for f'to determine the intervals on which each function fis increasing or decreasing. Then verify your algebraic answers with graphs from a calculator or graphing utility.

f(x)=cos2(x)

Short Answer

Expert verified

Ans: Increasing interval [2k+1,2k+3]

and decreasing elsewhere.

Step by step solution

01

Step 1. Given information:

f(x)=cos2(x)

02

Step 2. Finding the derivative of the function:

f(x)=cos2(x)f'(x)=2cosx.sinxf'(x)=sin2xletf'(x)=0∴sin2x=0⇒2x=nπ⇒x=nπ2[wherenisanyinteger]⇒x=2k+1x=2k+1

03

Step 3. Finding increasing and decreasing intervals: 

Intervals of the given function :

f'(x)hasx=2k+2f'(2k+2)=Ï€2cos(Ï€2(2k+2))=Ï€2cos(k+1)Ï€=-Ï€2whenk=1,3,5,...Ï€2whenk=2,4,6,...

f(x)is increasing on the interval2k+1,2k+3

and decreasing elsewhere.

04

Step 4. Verifying algebraic answers with graphs :

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