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In Exercises 19–26, write down an equation that relates the two quantities described. Then use implicit differentiation to obtain a relationship between the rates at which the quantities change over time.

The volume V and radius r of a cylinder with a fixed height of 10 units.

Short Answer

Expert verified

The equation that relates the volume Vand the radius r of the cylinder is V=10Ï€°ù2.

The derivativedVdtanddrdtare related by dVdt=20Ï€°ùdrdt.

Step by step solution

01

Step 1. Given information.

The height of a cylinder is 10 units.

02

Step 2. Formula used.

The volume of a cylinder is V=Ï€°ù2hcu. units.

03

Step 3. Apply the value of h.

Apply the value of h=10in V=Ï€°ù2has follows.

V=Ï€°ù2hV=Ï€°ù210V=10Ï€°ù2

The equation that relates the volumeV and radiusr of the cylinder isV=10Ï€°ù2.

04

Step 4. Apply the differentiation.

Apply the differentiation to V=10Ï€°ù2 with respect to t as follows.

ddtV=ddt10Ï€°ù2dVdt=20Ï€°ùdrdt

The derivativedVdtanddrdtare related by.

05

Step 5. Conclusion.

The equation that relates the volume V and the radius r of the cylinder is V=10Ï€°ù2.

The derivativedVdtanddrdtare related bydVdt=20Ï€°ùdrdt.

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