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91Ó°ÊÓ

For each function f that follows, construct sign charts forf, f',and f '', if possible. Examine function values or limits at any interesting values and at ±∞. Then interpret this information to sketch a labeled graph of f.

f(x)=lnx2+1.

Short Answer

Expert verified

Sign charts forf, f',and f ''are the following.

Graph of function is following.

Step by step solution

01

Step 1. Given information. 

The given function isf(x)=lnx2+1.

02

Step 2. Roots of the function. 

Equate the function to zero.

f(x)=0lnx2+1=0x2+1=1x2=0x=0

The root of the function is x=0.

03

Step 3. critical points of the function. 

Determine the first derivative of the function.

f'(x)=ddxlnx2+1=2xx2+1

critical points of the function.

f'(x)=02xx2+1=02x=0x=0

so the function has critical point atx=0.

04

Step 4. inflection point of the function.  

find the second derivative of the function.

f''(x)=ddx2xx2+1=-2x2-1x2+12

the inflection point of the function.

f''(x)=0-2x2-1x2+12=0x2-1=0x2=1x=±1

So the function has inflection points at x=±1.

So the sign chart is the following.

05

Step 5. Graph of function. 

The graph of the function is the following.

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