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Chapter 3: Q. 14 (page 260)

Find the critical points of the function

f'(x)=(x-1)(x-2)x-3

Short Answer

Expert verified

Thecriticalpointsofthefunctionisx=1,2

Step by step solution

01

Step 1. Given 

The given function isf'(x)=(x-1)(x-2)x-3.

02

Step 2. Calculation 

"Apointx=cinthedomainoffiscalledacriticalpointoffiff'(c)=0orf'(c)doesnotexist.Now,equatef'(x)=0((x-1)(x-2))(x-3)=0(x-1)(x-2)=0x=1,x=2Therefore,thecriticalpointsofthefunctionisx=1,2

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