91Ó°ÊÓ

The given sign chart is

To sketch the possible graph off, we will use theorem 3.6 and 3.10.

Theorem 3.6 states that the Derivative Measures Where a Function is Increasing or Decreasing, letf be a function that is differentiable on an intervalI.

(a) If $f\text{'}$is positive in the interior of I, then f is increasing onI.

(b) If $f\text{'}$is negative in the interior of I, then f is decreasing onI.

(c) If $f\text{'}$is zero in the interior of I, then f is constant onI.

Theorem 3.10 states that the Second Derivative Determines Concavity, suppose bothf and $f\text{'}$are differentiable on an interval I.

(a) If $f\text{'}\text{'}$is positive on I, thenf is concave up onI.

(b) If $f\text{'}\text{'}$is negative onI, thenf is concave down onI.

From the given chart, we conclude that

$f\text{'}$is positive on the interval $\left(-∞,0\right)$and negative on the interval $\left(0,∞\right).$Thus, f will we increase on the positve intervals and decrease on the negative intervals.

$f\text{'}\text{'}$is positive on the intervals $\left(-∞,-1\right)\mathrm{and}\left(1,∞\right)$and negative on the interval $\left(-1,1\right).$ Thus, fwill be concave up on the positive intervals and concave down on the negative intervals.

The graph has roots at $x=-1,$a local minimum at $x=0,$and inflection points at$x=-1and1.$

The graph is