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Use Theorem 6.7 to prove that a circle of radius 5 has circumference10Ï€.

Short Answer

Expert verified

Circle of radius 5 has circumference 10Ï€.

Step by step solution

01

Step 1. Given Information 

Circle of radius 5.

02

Step 2. Proving circumference of circle of radius 5 to be 10π.

Thenthearclengthoff(x)fromx=atox=bcanberepresentedbythedefiniteintegral:∫ab1+(f'(x))2dxEquationofcircleofradius5is:x2+y2=52Therefore,y=52-x2=f(x)andf'(x)=-x52-x2Circumferenceofthecircleistwicethearclengthfromx=-5tox=5off(x)Therefore,C=2∫-551+(f'(x))2dxC=2∫-551+-x52-x22dxC=2∫-551+x252-x2dxC=2∫-5552-x2+x52-x22dxC=2∫-55552-x2dxPut,x=5sint,dx=5costdtLimitsofintegrationchangeto-π2toπ2C=2∫-π2π25×5×cost52-(5sint)2dtC=2∫-π2π25×5×cost52-(5sint)2dtC=10∫-π2π25×cost5×costdtC=10∫-π2π21dtC=10t-π2π2C=10π2--π2C=10π

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