Chapter 2: Problem 25
Find \(f^{\prime}(x)\) by using the definition of the derivative. [Hint: See Example 4.] $$ f(x)=x^{2}-3 x+5 $$
Short Answer
Expert verified
The derivative is \( f^{\prime}(x) = 2x - 3 \).
Step by step solution
01
Recall the Definition of Derivative
The derivative of a function \( f(x) \) at a point \( x \) is given by the limit formula: \[ f^{\prime}(x) = \lim_{{h \to 0}} \frac{f(x+h) - f(x)}{h}. \] This definition will be used to find the derivative for the function \( f(x) = x^2 - 3x + 5 \).
02
Substitute into the Definition
Substitute \( x+h \) into the function to get \( f(x+h) = (x+h)^2 - 3(x+h) + 5 \). Expand this and simplify to find \( f(x+h) - f(x) \).
03
Simplify \( f(x+h) \)
Compute \( f(x+h) = (x+h)^2 - 3(x+h) + 5 \). Expanding gives: \[ f(x+h) = x^2 + 2xh + h^2 - 3x - 3h + 5. \]
04
Compute \( f(x+h) - f(x) \)
Subtract \( f(x) = x^2 - 3x + 5 \) from \( f(x+h) \) to obtain: \[ f(x+h) - f(x) = (x^2 + 2xh + h^2 - 3x - 3h + 5) - (x^2 - 3x + 5). \] Simplifying yields \( f(x+h) - f(x) = 2xh + h^2 - 3h \).
05
Divide by \( h \) and Simplify
According to the limit definition, divide the result by \( h \):\[ \frac{f(x+h) - f(x)}{h} = \frac{2xh + h^2 - 3h}{h} = 2x + h - 3. \]
06
Take the Limit as \( h \to 0 \)
Finally, take the limit of the expression as \( h \to 0 \): \[ \lim_{{h \to 0}} (2x + h - 3) = 2x - 3. \] This gives us \( f^{\prime}(x) = 2x - 3. \)
Unlock Step-by-Step Solutions & Ace Your Exams!
-
Full Textbook Solutions
Get detailed explanations and key concepts
-
Unlimited Al creation
Al flashcards, explanations, exams and more...
-
Ads-free access
To over 500 millions flashcards
-
Money-back guarantee
We refund you if you fail your exam.
Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!
Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Definition of Derivative
The derivative is a fundamental concept in calculus, which represents the rate of change of a function with respect to a variable. It's like figuring out how fast something is changing at a specific moment. To find the derivative of a function \( f(x) \) at a particular point \( x \), we use a specific mathematical formula. This formula is expressed as: \[\]
- \( f^{\prime}(x) = \lim_{{h \to 0}} \frac{f(x+h) - f(x)}{h} \)
Limit Process
The limit process is a method to find what value a function approaches as the variable approaches a certain point. In the context of derivatives, it helps us find the derivative by understanding how a function behaves as its input gets infinitely close to a specific value.When we have an expression like \( \lim_{{h \to 0}} \frac{f(x+h) - f(x)}{h} \), the limit tells us what \( \frac{f(x+h) - f(x)}{h} \) equals as \( h \) becomes extremely small.
- The expression \( \frac{f(x+h) - f(x)}{h} \) is called the difference quotient.
- As \( h \to 0 \), the difference quotient approaches the slope of the tangent to the curve at \( x \).
Polynomial Function Differentiation
Differentiation of polynomial functions, like \( f(x) = x^2 - 3x + 5 \), involves applying the definition of the derivative. However, once we get the hang of it, it becomes intuitive and slightly mechanical.Polynomials are made up of terms like constants, \( x^n \), linear terms like \( 3x \), etc. Differentiating them involves using the power rule, which states:
- If \( f(x) = x^n \), then \( f^{\prime}(x) = n \cdot x^{n-1} \).
- The derivative of \( x^2 \) is \( 2x \) (since \( 2 \cdot x^{1} = 2x \)).
- The derivative of \( -3x \) is \( -3 \) (as linear terms like \( ax \) differentiate to \( a \)).
- The derivative of a constant like 5 is \( 0 \).