/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 71 Determine whether each function ... [FREE SOLUTION] | 91Ó°ÊÓ

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Determine whether each function is continuous or discontinuous. If discontinuous, state where it is discontinuous. $$ \begin{array}{l} f(x)=\left\\{\begin{array}{ll} 3-x & \text { if } x \leq 4 \\ 10-2 x & \text { if } x>4 \end{array}\right.\\\ \text { [Hint: See Exercise 37.] } \end{array} $$

Short Answer

Expert verified
The function is discontinuous at \( x = 4 \).

Step by step solution

01

Identify the pieces of the function

The function is given as a piecewise function: \( f(x) = 3 - x \) if \( x \leq 4 \) and \( f(x) = 10 - 2x \) if \( x > 4 \). We will check for continuity at the point where the pieces meet, which is \( x = 4 \).
02

Evaluate the left-hand limit as x approaches 4

Calculate the left-hand limit where \( x \leq 4 \), so we use \( f(x) = 3-x \). As \( x \to 4^- \), \( \lim_{x \to 4^-} f(x) = 3 - 4 = -1 \).
03

Evaluate the right-hand limit as x approaches 4

Calculate the right-hand limit where \( x > 4 \), so we use \( f(x) = 10 - 2x \). As \( x \to 4^+ \), \( \lim_{x \to 4^+} f(x) = 10 - 2(4) = 2 \).
04

Evaluate f(4)

Since \( x = 4 \) is part of the domain where \( x \leq 4 \), we use \( f(x) = 3 - x \). Thus, \( f(4) = 3 - 4 = -1 \).
05

Compare limits and function value at x=4

For continuity at \( x = 4 \), the left-hand limit, right-hand limit, and \( f(4) \) must all be equal. Here, \( \lim_{x \to 4^-} f(x) = -1 \), \( \lim_{x \to 4^+} f(x) = 2 \), and \( f(4) = -1 \). Since the limits are not equal, the function is discontinuous at \( x = 4 \).
06

State the result of discontinuity

The function is discontinuous at \( x = 4 \) because the left-hand limit, \( f(4) \), and the right-hand limit are not all equal.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Piecewise Functions
Piecewise functions are special kinds of functions that use different expressions or rules for different intervals of their domain. These functions essentially "piece" together multiple sub-functions to cover the entire domain.

Consider the function given in the exercise:
  • For values where \( x \leq 4 \), the function is expressed as \( 3 - x \), meaning any input below or equal to 4 uses this formula to determine the output.
  • For values where \( x > 4 \), the function switches to a different formula: \( 10 - 2x \).
Understanding piecewise functions is essential for determining how they behave at the points where the pieces change or meet. In many cases, the task is to analyze the transition at these boundary points. By doing so, we can determine if the function is continuous at these junctions or if there are any breaks or jumps in its graph.
Limits and Continuity
Limits and continuity are closely related concepts in calculus that help us understand the behavior of functions at specific points or as they approach specific values.

To determine continuity at a point, the following must hold:
  • The left-hand limit, as the function approaches the point from the left, must exist.
  • The right-hand limit, as the function approaches from the right, must also exist.
  • The actual value of the function at that point should equal both the left-hand and right-hand limits.
In simpler words, if these three values are the same, the function is continuous at that point.

In the exercise, evaluating the limits around \( x = 4 \) showed that the left-hand limit \( \lim_{x \to 4^-} f(x) = -1 \) and the right-hand limit \( \lim_{x \to 4^+} f(x) = 2 \) are not equal. This discrepancy causes the piecewise function to be discontinuous at \( x = 4 \).
Discontinuous Functions
Discontinuous functions are ones that have breaks, jumps, or holes at certain points in their domain. These interruptions in the graph of the function mean that they aren't smooth or unbroken throughout the entire domain.

A discontinuity occurs when the criteria for continuity are not met. Such as when the left-hand and right-hand limits do not match, or if they're not equal to the actual function’s value at that point.

In the step-by-step solution of the exercise, the piecewise function:
  • It was evaluated that \( x = 4 \) is a point of discontinuity because the left-hand limit and the right-hand limit are different.
  • This type of discontinuity is specifically a "jump discontinuity," where the function has two different values that it approaches from either side of the point.
Understanding discontinuities is crucial, especially when graphing functions or solving real-world problems, as they indicate where a function changes behavior, or fails to follow a 'normal' expected pattern.

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Most popular questions from this chapter

Derive the Quotient Rule from the Product Rule as follows. a. Define the quotient to be a single function, $$ Q(x)=\frac{f(x)}{g(x)} $$ b. Multiply both sides by \(g(x)\) to obtain the equation \(Q(x) \cdot g(x)=f(x) .\) c. Differentiate each side, using the Product Rule on the left side. d. Solve the resulting formula for the derivative \(Q^{\prime}(x) .\) e. Replace \(Q(x)\) by \(\frac{f(x)}{g(x)}\) and show that the resulting formula for \(Q^{\prime}(x)\) is the same as the Quotient Rule. Note that in this derivation when we differentiated \(Q(x)\) we assumed that the derivative of the quotient exists, whereas in the derivation on pages \(135-136\) we proved that the derivative exists.

The percentage of people in the United States who are immigrants (that is, were born elsewhere) for different decades is shown below. These percentages are approximated by the function \(f(x)=\frac{1}{2} x^{2}-3.7 x+12\), where \(x\) stands for the number of decades since 1930 (so that, for example, \(x=5\) would stand for 1980 ). a. Find \(f^{\prime}(x)\) using the definition of the derivative b. Evaluate the derivative at \(x=1\) and interpret the result. c. Find the rate of change of the immigrant percentage in the year 2010 .

True or False: If \(f(2)=5\), then \(\lim _{x \rightarrow 2} f(x)=5\).

For a function \(f(x)\), if \(f\) is in widgets and \(x\) is in blivets, what are the units of the derivative \(f^{\prime}(x)\), widgets per blivet or blivets per widget?

Use the Generalized Power Rule to find the derivative of each function. $$ f(x)=x^{2} \sqrt{1+x^{2}} $$

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