/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 78 Simplify. $$ \frac{\left(u^{... [FREE SOLUTION] | 91Ó°ÊÓ

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Simplify. $$ \frac{\left(u^{3} v w^{2}\right)^{2}}{9\left(u^{2} w\right)^{2}} $$

Short Answer

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\( \frac{u^2 v^2 w^2}{9} \)

Step by step solution

01

Apply the Power of a Power Rule

The expression is \( \frac{\left(u^3 v w^2\right)^2}{9(u^2 w)^2} \). We first apply the power of a power rule, \((a^m)^n = a^{m \cdot n}\), to the numerator and denominator separately. For the numerator, \((u^3 v w^2)^2 = u^{3 \cdot 2} v^{1 \cdot 2} w^{2 \cdot 2} = u^6 v^2 w^4\). For the denominator, \((u^2 w)^2 = u^{2 \cdot 2} w^{1 \cdot 2} = u^4 w^2\).
02

Write the Simplified Expression

The expression after applying the power rule becomes: \( \frac{u^6 v^2 w^4}{9 u^4 w^2} \).
03

Simplify the Fraction by Dividing Like Bases

Divide the like bases in the numerator and denominator. Starting with \( u^6 \) and \( u^4 \): \( \frac{u^6}{u^4} = u^{6-4} = u^2 \). For \( w^4 \) and \( w^2 \): \( \frac{w^4}{w^2} = w^{4-2} = w^2 \). The variable \( v \) has no corresponding base in the denominator, so it remains \( v^2 \).
04

Final Simplified Expression

Combine the results of the simplification: \( \frac{u^2 v^2 w^2}{9} \).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Power of a Power Rule
When working with exponents, you'll often come across the situation where you have a power of a power, like \((a^m)^n\). This is handled with the Power of a Power Rule. The rule states that you multiply the exponents together: \((a^m)^n = a^{m\cdot n}\). For example, if you see \((x^3)^2\), you multiply the exponents (3 and 2) to get \(x^6\). This rule makes the process of simplifying expressions with nested exponents straightforward and helps you to reduce the complexity of expressions.In our given exercise, we used this rule both in the numerator and the denominator: - Numerator: \((u^3 v w^2)^2 = u^{3 \cdot 2} v^{1 \cdot 2} w^{2 \cdot 2} = u^6 v^2 w^4\).- Denominator: \((u^2 w)^2 = u^{2 \cdot 2} w^{1 \cdot 2} = u^4 w^2\).This step is crucial in algebraic simplification as it sets the ground for further reduction of the expression.
Exponent Rules
Exponent rules are fundamental in algebra. They help us manipulate expressions involving powers efficiently. These rules are:
  • Product of Powers Rule: \(a^m \cdot a^n = a^{m+n}\)
  • Quotient of Powers Rule: \(\frac{a^m}{a^n} = a^{m-n}\), where \(a eq 0\)
  • Power of a Power Rule: \((a^m)^n = a^{m\cdot n}\)
  • Zero Exponent Rule: \(a^0 = 1\).
In the context of the expression we simplified, the quotient of powers rule was particularly important. For example:- Simplifying \(\frac{u^6}{u^4}\) resulted in \(u^{6-4} = u^2\).- Similarly, for \(w\), \(\frac{w^4}{w^2}\) became \(w^{4-2} = w^2\).Applying these rules allows us to combine and simplify terms into a less complicated expression, making complex algebra problems manageable.
Fraction Simplification
Simplifying fractions in algebra often involves reducing expressions by canceling shared factors between the numerator and the denominator. Here's how you approach it:- Identify common bases and use exponent rules like the Quotient of Powers Rule.- Factor out the greatest common factors if possible.In fraction simplification for our problem, the idea was to reduce the fractions to their simplest form by:- Beginning with the individual variable terms: for \(u^6/u^4\), subtract exponents to simplify to \(u^2\).- Next, handling other terms: \(w^4/w^2\) diminishes to \(w^2\).- Variables exclusive to the numerator like \(v^2\) stay unchanged as there's no corresponding term in the denominator.Fraction simplification is central to algebra because it streamlines expressions, making them easier to evaluate and understand. After completing this simplification, the expression appears much tidier as \(\frac{u^2 v^2 w^2}{9}\). By consistently applying these principles, one can handle increasingly complex algebraic operations with confidence.

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Most popular questions from this chapter

BUSINESS: Straight-Line Depreciation Straight-line depreciation is a method for estimating the value of an asset (such as a piece of machinery) as it loses value ( \({ }^{\prime \prime}\) depreciates" \()\) through use. Given the original price of an asset, its useful lifetime, and its scrap value (its value at the end of its useful lifetime), the value of the asset after \(t\) years is given by the formula: $$ \begin{aligned} \text { Value }=(\text { Price })-&\left(\frac{(\text { Price })-(\text { Scrap value })}{(\text { Useful lifetime })}\right) \cdot t \\ & \text { for } 0 \leq t \leq(\text { Useful lifetime }) \end{aligned} $$ a. A newspaper buys a printing press for $$\$ 800,000$$ and estimates its useful life to be 20 years, after which its scrap value will be $$\$ 60,000$$. Use the formula above Exercise 63 to find a formula for the value \(V\) of the press after \(t\) years, for \(0 \leq t \leq 20\) b. Use your formula to find the value of the press after 10 years. c. Graph the function found in part (a) on a graphing calculator on the window \([0,20]\) by \([0,800,000] .\) [Hint: Use \(x\) instead of \(t\).]

Find the \(x\) -intercept \((a, 0)\) where the line \(y=m x+b\) crosses the \(x\) -axis. Under what condition on \(m\) will a single \(x\) -intercept exist?

Use the TABLE feature of your graphing calculator to evaluate \(\left(1+\frac{1}{x}\right)^{x}\) for values of \(x\) such as \(100,10,000,1,000,000\), and higher values. Do the resulting numbers seem to be approaching a limiting value? Estimate the limiting value to five decimal places. The number that you have approximated is denoted \(e\), and will be used extensively in Chapter \(4 .\)

The intersection of an isocost line \(w L+r K=C\) and an isoquant curve \(K=a L^{b}\) (see pages 18 and 32 ) gives the amounts of labor \(L\) and capital \(K\) for fixed production and cost. Find the intersection point \((L, K)\) of each isocost and isoquant. [Hint: After substituting the second expression into the first, multiply through by \(L\) and factor.] $$ 5 L+4 K=120 \text { and } K=180 \cdot L^{-1} $$

ECONOMICS: Does Money Buy Happiness? Several surveys in the United States and Europe have asked people to rate their happiness on a scale of \(3={ }^{\prime \prime}\) very happy," \(2=\) "fairly happy," and \(1={ }^{\prime \prime}\) not too happy," and then tried to correlate the answer with the person's income. For those in one income group (making $$\$ 25,000$$ to $$\$ 55,000$$ ) it was found that their "happiness" was approximately given by \(y=0.065 x-0.613\). Find the reported "happiness" of a person with the following incomes (rounding your answers to one decimal place). a. $$\$ 25,000$$ b. $$\$ 35,000$$ c. $$\$ 45,000$$

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