Chapter 1: Problem 2
Evaluate each expression without using a calculator. $$ \left(5^{2} \cdot 4\right)^{2} $$
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These are the key concepts you need to understand to accurately answer the question.
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Chapter 1: Problem 2
Evaluate each expression without using a calculator. $$ \left(5^{2} \cdot 4\right)^{2} $$
These are the key concepts you need to understand to accurately answer the question.
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Use your graphing calculator to graph the following four equations simultaneously on the window \([-10,10]\) by \([-10,10]:\) $$ \begin{array}{l} y_{1}=3 x+4 \\ y_{2}=1 x+4 \end{array} $$ \(y_{3}=-1 x+4\) (Use \((-)\) to get \(-1 x\). \()\) $$ y_{4}=-3 x+4 $$ a. What do the lines have in common and how do they differ? b. Write the equation of a line through this \(y\) -intercept with slope \(\frac{1}{2}\). Then check your answer by graphing it with the others.
For any \(x\), the function \(\operatorname{INT}(x)\) is defined as the greatest integer less than or equal to \(x\). For example, \(\operatorname{INT}(3.7)=3\) and \(\operatorname{INT}(-4.2)=-5\) a. Use a graphing calculator to graph the function \(y_{1}=\operatorname{INT}(x) .\) (You may need to graph it in DOT mode to eliminate false connecting lines.)
If a linear function is such that \(f(4)=7\) and \(f(6)=11\), then \(f(5)=? \quad[\) Hint \(:\) No work necessary.]
GENERAL: Longevity When a person reaches age 65 , the probability of living for another \(x\) decades is approximated by the function \(f(x)=-0.077 x^{2}-0.057 x+1 \quad\) (for \(\left.0 \leq x \leq 3\right)\) Find the probability that such a person will live for another: a. One decade. b. Two decades. c. Three decades.
$$ \text { If } f(x)=a x, \text { then } f(f(x))=? $$
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