Chapter 6: Problem 37
Find each integral by integration by parts or a substitution, as appropriate. a. \(\int x e^{x^{2}} d x\) b. \(\int \frac{(\ln x)^{3}}{x} d x\) c. \(\int x^{2} \ln 2 x d x\) d. \(\int \frac{e^{x}}{e^{x}+4} d x\)
Short Answer
Expert verified
a. \( \frac{1}{2} e^{x^2} + C \); b. \( \frac{(\ln x)^4}{4} + C \); c. \( \frac{x^3 \ln 2x}{3} - \frac{x^3}{9} + C \); d. \( \ln |e^x+4| + C \).
Step by step solution
01
Recognize the need for substitution for part (a)
The integral \( \int x e^{x^2} \, dx \) suggests a substitution because of the composition \( e^{x^2} \). We use the substitution \( u = x^2 \). This implies \( du = 2x \, dx \), or \( x \, dx = \frac{1}{2} \, du \).
02
Substitute and integrate for part (a)
Substitute \( u = x^2 \) into the integral, which gives \( \int x e^{x^2} \, dx = \frac{1}{2} \int e^u \, du \). The integral of \( e^u \) is \( e^u \), so the result is \( \frac{1}{2} e^u + C \). Substituting back, we get \( \frac{1}{2} e^{x^2} + C \).
03
Recognize the integral form of part (b)
The integral \( \int \frac{(\ln x)^3}{x} \, dx \) suggests using substitution for the logarithmic function. Use \( u = \ln x \), which implies \( du = \frac{1}{x} \, dx \).
04
Substitute and integrate for part (b)
Substitute \( u = \ln x \) into the integral, resulting in \( \int u^3 \, du \). The antiderivative of \( u^3 \) is \( \frac{u^4}{4} + C \). Substituting back, the solution is \( \frac{(\ln x)^4}{4} + C \).
05
Use integration by parts for part (c)
The integral \( \int x^2 \ln 2x \, dx \) suggests integration by parts since it involves a polynomial and a logarithm. Let \( u = \ln 2x \) and \( dv = x^2 \, dx \). Then \( du = \frac{1}{x} \, dx \) and \( v = \frac{x^3}{3} \).
06
Integrate by parts for part (c)
Apply integration by parts: \( \int u \, dv = uv - \int v \, du \). This gives \( \frac{x^3 \ln 2x}{3} - \int \frac{x^3}{3} \cdot \frac{1}{x} \, dx \). Simplifying the integral portion gives \( \frac{x^3}{3} - \int \frac{x^2}{3} \, dx \). Finally, evaluate the integral to get \( \frac{x^3 \ln 2x}{3} - \frac{x^3}{9} + C \).
07
Recognize the substitution for part (d)
The integral \( \int \frac{e^x}{e^x+4} \, dx \) suggests substituting the expression in the denominator. Let \( u = e^x+4 \), so \( du = e^x \, dx \).
08
Substitute and integrate for part (d)
Substitute \( u = e^x+4 \) into the integral, which becomes \( \int \frac{1}{u} \, du \). The antiderivative of \( \frac{1}{u} \) is \( \ln |u| + C \). Substituting back, we find \( \ln |e^x + 4| + C \).
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Substitution Method
The substitution method is often utilized when dealing with integrals that contain a composition of functions. In the case of the integral \( \int x e^{x^2} \, dx \), the substitution method is beneficial because it simplifies the expression. Here, we use the substitution \( u = x^2 \), which transforms the integral from a more complex form into a simpler one, \( \int e^u \, du \). This substitution is powerful as it helps reduce the integral into a standard form that is easier to evaluate.
The key to using substitution effectively is to choose a substitution that simplifies the function:
The key to using substitution effectively is to choose a substitution that simplifies the function:
- Identify a function within the integrand that, when substituted, reduces complexity.
- Determine the differential \( du \) in terms of \( dx \).
- Rewrite the entire integral in terms of \( u \).
- Integrate and substitute back to find the solution in the original variable.
Integration by Parts
Integration by parts is a technique derived from the product rule of differentiation, used particularly for integrals of products of functions. For instance, in solving \( \int x^2 \ln 2x \, dx \), integration by parts proves effective because of the presence of a polynomial and a logarithmic function.
The formula for integration by parts is:
The formula for integration by parts is:
- \[ \int u \, dv = uv - \int v \, du \]
- Choose \( u \) as a function that simplifies upon differentiation and \( dv \) as one that is easy to integrate.
- Calculate \( du \) and \( v \).
- Plug these into the integration by parts formula.
- Simplify and resolve the resulting integral.
Antiderivatives
Antiderivatives, also known as indefinite integrals, are the reverse process of differentiation. They provide a function whose derivative is the original function. For example, knowing that the derivative of \( e^x \) is \( e^x \), the integral of \( e^x \) results in its antiderivative \( e^x + C \), where \( C \) is the constant of integration.
When solving integrals, finding the antiderivative is often the core goal. Understanding antiderivatives involves:
When solving integrals, finding the antiderivative is often the core goal. Understanding antiderivatives involves:
- Recognizing the function within the integrand whose derivative matches the given function.
- Applying known integral rules to find the antiderivative.
- Adding the constant \( C \) to signify the family of antiderivatives.
Logarithmic Integration
Logarithmic integration is particularly relevant when dealing with functions that involve natural logs. An excellent example is \( \int \frac{(\ln x)^3}{x} \, dx \), where substitution helps convert the integral into a more manageable form. Here, let \( u = \ln x \), turning the integral into \( \int u^3 \, du \).
Once in this form, integration becomes more straightforward:
Once in this form, integration becomes more straightforward:
- Use substitution to simplify functions intricately linked with logarithms.
- Recognize the differential \( du \) derived from the substitution.
- Integrate using standard rules for polynomials transformed through substitution.