/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 17 Evaluate each improper integral ... [FREE SOLUTION] | 91Ó°ÊÓ

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Evaluate each improper integral or state that it is divergent. \(\int_{1}^{x} \frac{1}{x^{3}} d x\)

Short Answer

Expert verified
The integral converges to \( \frac{1}{2} \).

Step by step solution

01

Identify the Type of Improper Integral

This integral is improper due to the variable upper limit of integration, which tends toward infinity.
02

Set Up the Integral as a Limit

Evaluate the integral by taking the limit as the upper limit of integration approaches infinity: \[ \int_{1}^{\infty} \frac{1}{x^{3}} dx = \lim_{b \to \infty} \int_{1}^{b} \frac{1}{x^{3}} dx \]
03

Determine the Indefinite Integral

Find the indefinite integral of \( \frac{1}{x^{3}} \):\[ \int \frac{1}{x^{3}} dx = -\frac{1}{2x^{2}} + C \]
04

Evaluate the Definite Integral

Substitute the indefinite integral back into the limit:\[ \lim_{b \to \infty} \left(-\frac{1}{2b^{2}} - \left(-\frac{1}{2 \times 1^{2}}\right)\right) \] This simplifies to:\[ \lim_{b \to \infty} \left(-\frac{1}{2b^{2}} + \frac{1}{2}\right) \]
05

Evaluate the Limit

Calculate the limit as \( b \to \infty \):Since \( \frac{1}{b^2} \to 0 \) as \( b \to \infty \), the expression simplifies to:\[ \frac{1}{2} - 0 = \frac{1}{2} \]
06

Conclusion

The integral converges to \( \frac{1}{2} \).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Integration Techniques
Improper integrals often require specific integration techniques to evaluate them. One crucial approach is to transform the improper integral into a proper form using limits. When dealing with improper integrals, such as those with infinite bounds, we set up the integral as a limit.
For example, in the given problem, we set the upper limit to infinity using a variable, say \( b \), and write:
\[ \int_{1}^{\infty} \frac{1}{x^3} \, dx = \lim_{b \to \infty} \int_{1}^{b} \frac{1}{x^3} \, dx \]
This requires us to find the indefinite integral first. Even if an integral seems complex, breaking it down into smaller steps by taking derivatives and applying integration rules can significantly simplify the process.
  • Apply basic formulas: Such as finding the antiderivative of \( \frac{1}{x^3} \), which is \( -\frac{1}{2x^2} \).
  • Substitute boundaries back into your integral to form a limit problem.
Calculus Limits
The concept of limits is fundamental in evaluating improper integrals, especially when bounds reach infinity. Calculus limits allow us to understand the behavior of a function as the input approaches a specific value, including infinity.
In the context of improper integrals, once the indefinite integral is obtained, limits are used to evaluate the extent to which the function approaches a value. Taking the limit of the evaluated integral as \( b \to \infty \) ensures that we correctly understand the behavior at infinity.When evaluating a limit:
  • Consider the result of plugging in infinity. For instance, \( \frac{1}{b^2} \) tends to zero as \( b \) becomes very large.
  • The result of the limit in the integral process indicates whether the integral converges (lands on a finite number) or diverges (goes off to infinity).

In our example, since \( \lim_{b \to \infty} \left(-\frac{1}{2b^2} + \frac{1}{2}\right) \) simplifies to \( \frac{1}{2} \), we confirm the integration process was properly handled, and the function converges.
Convergence and Divergence
Convergence and divergence are essential proprieties when dealing with improper integrals. They help us determine whether a function has a finite area under its curve over an infinite domain.
An integral is deemed convergent if the result is a finite number. In contrast, it is divergent if the integral's result is infinite. Recognizing these qualities allows us to decide how practical or significant the results are in physical and mathematical terms.
  • Convergent Integral: In our example, the integral \( \int_{1}^{\infty} \frac{1}{x^3} \, dx \) converges to \( \frac{1}{2} \), a finite value. Therefore, the area under the curve from 1 to infinity is finite.
  • Divergent Integral: If an integral had an outcome of infinity, such as \( \int_{1}^{\infty} \frac{1}{x} \, dx \), it would be divergent because the sum expands to infinity.
Understanding these concepts broadens application possibilities across various scientific and engineering domains, providing insights into phenomena that extend over large ranges or prolonged periods.

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