Chapter 1: Problem 55
Find a formula for the described function and state its domain. Express the area of an equilateral triangle as a function of the length of a side.
Short Answer
Expert verified
Area formula: \( A(s) = \frac{\sqrt{3}}{4} s^2 \); domain: \( s \geq 0 \).
Step by step solution
01
Understanding an Equilateral Triangle
An equilateral triangle has all three sides of equal length. Let's denote the length of each side as \( s \). Furthermore, in an equilateral triangle, all angles are equal, each measuring 60 degrees.
02
Area Formula for a Triangle
The general formula for the area \( A \) of a triangle is given by: \[ A = \frac{1}{2} \text{base} \times \text{height}. \] Since we need the height, we'll calculate it using the properties of an equilateral triangle.
03
Calculate the Height of the Equilateral Triangle
To find the height \( h \) of an equilateral triangle, drop a perpendicular from one vertex to the opposite side, dividing the triangle into two 30-60-90 right triangles. Using the ratio in a 30-60-90 triangle, where the side opposite the 60-degree angle (the height) is \( \frac{\sqrt{3}}{2} \) times the hypotenuse (which is \( s \)), the height \( h \) is: \[ h = \frac{\sqrt{3}}{2} s. \]
04
Substitute the Height into the Area Formula
Replace the base with \( s \) and height with \( \frac{\sqrt{3}}{2} s \) in the triangle area formula: \[ A = \frac{1}{2} \times s \times \frac{\sqrt{3}}{2} s. \]
05
Simplify the Expression for Area
Simplify the expression: \[ A = \frac{1}{2} \times s \times \frac{\sqrt{3}}{2} s = \frac{\sqrt{3}}{4} s^2. \] So, the area of an equilateral triangle as a function of the side length \( s \) is given by \( A(s) = \frac{\sqrt{3}}{4} s^2 \).
06
State the Domain of the Function
The function \( A(s) = \frac{\sqrt{3}}{4} s^2 \) only makes sense for non-negative values of \( s \), as negative side lengths do not have real-world meaning in this context. Therefore, the domain of the function is \( s \geq 0 \).
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Function and Domain
A function is a relationship between two variables, typically written as \( f(x) \), where \( f \) is the function and \( x \) is the input variable. In simpler terms, a function produces an output for each input. For this exercise, we express the area of an equilateral triangle as a function of the length of its side. This means we define the area, \( A(s) \), in terms of \( s \), the side length.
The domain of a function refers to the set of possible input values (\( s \) in our case) for which the function is defined. Here, since side lengths cannot be negative, \( s \) must be a non-negative real number. Thus, the domain is expressed as \( s \geq 0 \). In this case, any non-negative \( s \) could be plugged into the function to return an area, making it physically meaningful for describing lengths.
The domain of a function refers to the set of possible input values (\( s \) in our case) for which the function is defined. Here, since side lengths cannot be negative, \( s \) must be a non-negative real number. Thus, the domain is expressed as \( s \geq 0 \). In this case, any non-negative \( s \) could be plugged into the function to return an area, making it physically meaningful for describing lengths.
30-60-90 Triangle Properties
A 30-60-90 triangle is a special right triangle with angles measuring 30, 60, and 90 degrees. The sides of this triangle have a unique ratio which is always the same: 1: \( \sqrt{3} \): 2. This ratio indicates that the shortest side (opposite the 30-degree angle) has a length of 1, while the side opposite the 60-degree angle is \( \sqrt{3} \) times as long, and the hypotenuse (the longest side) is twice as long as the shortest side.
In the context of an equilateral triangle, when we draw a height from one vertex to the opposite side, creating two 30-60-90 triangles, we can use these properties to find the height. Since the height is opposite the 60-degree angle, it is \( \frac{\sqrt{3}}{2} \) times the hypotenuse (the side \( s \) of the equilateral triangle). This gives us a height \( h = \frac{\sqrt{3}}{2}s \). This property is crucial for calculating the area of the equilateral triangle.
In the context of an equilateral triangle, when we draw a height from one vertex to the opposite side, creating two 30-60-90 triangles, we can use these properties to find the height. Since the height is opposite the 60-degree angle, it is \( \frac{\sqrt{3}}{2} \) times the hypotenuse (the side \( s \) of the equilateral triangle). This gives us a height \( h = \frac{\sqrt{3}}{2}s \). This property is crucial for calculating the area of the equilateral triangle.
Area Formula for Triangles
Calculating the area of a triangle involves using the basic formula: \( A = \frac{1}{2} \times \text{base} \times \text{height} \). For an equilateral triangle, every side is equal to the base \( s \). We learned earlier that our height \( h \) is \( \frac{\sqrt{3}}{2} s \).
Substituting these values into the area formula gives us:
Substituting these values into the area formula gives us:
- Base is \( s \)
- Height is \( \frac{\sqrt{3}}{2}s \).