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Find the exact value of each expression. (a) $$\ln (1 / e) (b) \log _{10} \sqrt{10}$$

Short Answer

Expert verified
(a) -1 (b) \(\frac{1}{2}\)

Step by step solution

01

Recall properties of logarithms for ln

To solve \( \ln(1/e) \), we can use the property of natural logarithms that states \( \ln(a/b) = \ln(a) - \ln(b) \). Here, we identify \( a = 1 \) and \( b = e \).
02

Simplify ln terms

We substitute into the formula: \( \ln(1) - \ln(e) \). We know that \( \ln(1) = 0 \) and \( \ln(e) = 1 \). Therefore, the expression simplifies to \( 0 - 1 = -1 \).
03

Use properties of logarithms for log base 10

To solve \( \log_{10} \sqrt{10} \), recall the property \( \log_b(a^n) = n\log_b(a) \). In this case, recognize that \( \sqrt{10} = 10^{1/2} \).
04

Apply the logarithm property

Using the brought up property, substitute to get \( \frac{1}{2} \log_{10}(10) \). Since \( \log_{10}(10) = 1 \), the expression simplifies to \( \frac{1}{2} \times 1 = \frac{1}{2} \).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Properties of Logarithms
Logarithms are powerful tools in simplifying expressions and solving equations where the variable is an exponent. One of the key features of logarithms is their properties, which allow us to manipulate and transform logarithmic expressions effectively. Here are some fundamental properties:
  • **Product Property**: This states that the logarithm of a product is equal to the sum of logarithms. Formally, \[ \log_b(xy) = \log_b(x) + \log_b(y) \]
  • **Quotient Property**: The logarithm of a quotient is the difference of logarithms: \[ \log_b\left(\frac{x}{y}\right) = \log_b(x) - \log_b(y) \]
  • **Power Property**: This property shows that the logarithm of a power can be expressed as a multiple of the exponent itself: \[ \log_b(x^n) = n \log_b(x) \]
These properties are foundational when working to simplify or manipulate logarithmic equations. In our exercise, we applied the quotient property and power property to find solutions efficiently.
Natural Logarithms
Natural logarithms are logarithms with the base of Euler's number \( e \). The symbol used is \( \ln \), which stands for "natural log." The number \( e \) is an irrational constant approximately equal to 2.71828. Natural logarithms are frequently used in calculus and mathematical modeling, especially involving exponential growth and decay.The beauty of natural logarithms lies in their simplifying power:
  • \( \ln(e^x) = x \): This property allows easy solving of equations where \( e \) is involved.
  • Special values include \( \ln(1) = 0 \) and \( \ln(e) = 1 \)
In our exercise, knowing that \( \ln(1) = 0 \) and \( \ln(e) = 1 \) allowed us to easily compute \( \ln(1/e) = -1 \) by applying the quotient property.
Logarithm Simplification
Simplifying logarithm expressions makes them easier to work with and solve. Simplification often involves applying logarithmic properties as mentioned earlier. These properties help break down complex logarithmic statements into manageable parts by converting operations like multiplication, division, and power raising into addition, subtraction, and multiplication.In the exercise given, we simplified the expression \( \log_{10} \sqrt{10} \) by recognizing that \( \sqrt{10} \) can be expressed as \( 10^{1/2} \). Using the power property, we converted this into \( \frac{1}{2} \log_{10}(10) \), which further simplifies into \( \frac{1}{2} \) since \( \log_{10}(10) = 1 \).Through understanding the relationships given by logarithmic properties, simplification becomes an intuitive process, allowing us to solve problems efficiently and accurately.

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