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Bacteria population If a bacteria population starts with 500 bacteria and doubles in size every half hour, then the number of bacteria after \(t\) hours is \(n=f(t)=500 \cdot 4^{t}.\) (See Exercise 1.4 \(.30 ) .\) (a) Find the inverse of this function and explain its meaning. (b) When will the population reach \(10,000 ?\)

Short Answer

Expert verified
(a) The inverse is \( t = \log_{4}(\frac{n}{500}) \); it gives time to population \( n \). (b) Population reaches 10,000 in \( 2.16 \) hours.

Step by step solution

01

Understanding the Function

The function given is \( n = f(t) = 500 \cdot 4^{t} \), which describes the number of bacteria \( n \) as a function of time \( t \) in hours. The initial population is 500, and it grows exponentially by a factor of 4 each hour.
02

Finding the Inverse Function

To find the inverse function, we solve the equation for \( t \) in terms of \( n \). Start by setting \( n = 500 \cdot 4^{t} \). Divide both sides by 500, resulting in \( \frac{n}{500} = 4^{t} \). Taking the logarithm base 4 of both sides gives \( \log_{4}\left(\frac{n}{500}\right) = t \). Thus, the inverse function is \( t = f^{-1}(n) = \log_{4}\left(\frac{n}{500}\right) \), which tells us the time \( t \) in hours to reach a population \( n \).
03

Solving for Population 10,000

To find when the population reaches 10,000, set \( n = 10,000 \) in the original function: \( 10,000 = 500 \cdot 4^{t} \). Divide both sides by 500, yielding \( \frac{10,000}{500} = 4^{t} \) or \( 20 = 4^{t} \). Use logarithms to solve for \( t \): \( t = \log_{4}(20) = \frac{\log_{10}(20)}{\log_{10}(4)} \). Calculating this gives \( t \approx 2.16 \) hours.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Exponential Growth
Exponential growth happens when the rate of increase of a quantity is proportional to its current value. This concept is common in nature. For instance, investments that earn interest over time or populations in favorable conditions. In our bacteria growth problem, the population doubles every half hour. Thus, after one full hour, the population size is quadrupled. This is mathematically expressed with the formula \( n = 500 \cdot 4^{t} \), where \( n \) is the population size and \( t \) represents time in hours.

Since the growth is exponential, each hour the population increases by a factor of 4. Here's how exponential growth typically works:
  • Start with an initial amount (in this case, 500 bacteria).
  • Apply a constant rate of growth (population quadruples every hour).
  • Repeat this growth rate over successive time periods.
In real-world situations, exponential growth cannot continue indefinitely due to constraints such as space and resources, but in simplified models like this one, it gives a clear picture of rapid population increase.
Logarithms
Logarithms are mathematical tools that handle exponential relationships. They help us solve equations where the unknown variable is an exponent. In logarithmic form, an equation like \( b^{x} = y \) can be rewritten as \( \log_{b}(y) = x \).

In the bacteria problem, finding the time \( t \) for a certain population size involves rewriting the exponential equation. We transformed \( 20 = 4^{t} \) into a logarithmic equation to solve for \( t \).
  • Divide the equation to isolate the exponential part: \( \frac{n}{500} = 4^{t} \).
  • Take the logarithm of both sides to solve for \( t \): \( \log_{4}\left(\frac{n}{500}\right) = t \).
  • Use change of base formula if needed: \( t = \frac{\log_{10}(20)}{\log_{10}(4)} \).
Logarithms effectively "undo" exponential phenomena, making them crucial for tasks like finding the time for a population to reach a certain size, or converting between linear and exponential forms of data. They can sometimes feel complex, but they become simpler with practice and are useful in many scientific and financial contexts.
Bacteria Population
The bacteria population in our problem provides a real-world context for the abstract concepts of exponential growth and logarithms. At the start, there are 500 bacteria, but in ideal conditions, without limitations, the population grows exponentially. This aligns with many natural phenomena, where populations might rapidly increase given no constraints such as food supply or space.

In this model, the bacteria demonstrate perfect exponential growth. Every half hour, the population doubles, remarkably increasing in size over a short time. This predicts that a starting population of 500 grows to 1,000 after half an hour, then to 4,000 after a full hour:
  • Start: 500 bacteria
  • Half Hour: 1,000 bacteria
  • Full Hour: 4,000 bacteria (as it doubles then doubles again)
Using the original function \( n = 500 \cdot 4^{t} \), we found the inverse to determine the time needed to reach 10,000 bacteria. This involves logarithms and tells us how quickly exponential growth escalates. Bacteria colonies often serve as perfect examples of exponential growth due to their rapid reproduction rates under optimal conditions.

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Most popular questions from this chapter

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