Chapter 1: Problem 28
Find an explicit formula for \(f^{-1}\) and use it to graph \(f^{-1}\) , \(f,\) and the line \(y=x\) on the same screen.To check your work, see whether the graphs of \(f\) and \(f^{-1}\) are reflections about the line $$f(x)=2-e^{x}$$
Short Answer
Expert verified
The inverse function is \( f^{-1}(x) = \ln(2 - x) \). Graphs of \( f \), \( f^{-1}, \) and the line \( y = x \) illustrate the reflection.
Step by step solution
01
Understand the Function Given
The function provided is \( f(x) = 2 - e^x \). This function is a combination of a constant and an exponential decay function.
02
Set Up the Inverse Function Equation
To find \( f^{-1} \), we start by setting \( y = f(x) = 2 - e^x \). Our objective is to express \( x \) in terms of \( y \).
03
Isolate Exponential Expression
Rearrange for the exponential term: \( y = 2 - e^x \) becomes \( e^x = 2 - y \). This change isolates the exponential function.
04
Solve for x Using the Natural Log
Take the natural logarithm of both sides to solve for \( x \): \( x = \ln(2 - y) \).
05
Express Inverse Function
Turn the expression around to state the inverse function \( f^{-1}(y) = \ln(2 - y) \). To align with standard notation, replace \( y \) with \( x \), giving \( f^{-1}(x) = \ln(2 - x) \).
06
Plot the Functions and Line y = x
To graph \( f \), \( f^{-1} \), and the line \( y = x \), use graphing software or tools. Note that the graph of \( f \) should be a reflection of \( f^{-1} \) about the line \( y = x \).
07
Verify Reflection Property
Verify whether \( f \) and \( f^{-1} \) are reflections over the line \( y = x \) by checking if corresponding points are symmetric concerning the line.
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Exponential Function
An exponential function is a mathematical function of the form \( f(x) = a \cdot e^{bx} \), where \( e \) is the mathematical constant approximately equal to 2.71828, and \( a \) and \( b \) are constants. The base of the natural exponent \( e \) gives these functions unique properties. In our exercise, the function \( f(x) = 2 - e^x \) includes an exponential decay term, \( e^x \), which decreases as \( x \) increases, causing the whole function to decrease.Exponential functions are characterized by:
- Rapid growth or decay: Depending on the coefficient, they can model steep increases or decreases over short intervals.
- A horizontal asymptote: As \( x \) approaches positive infinity, the function approaches a constant value.
Graph Reflection
When we talk about graph reflection, we mean flipping a graph over a specific line so that each point on the graph has a symmetrical counterpart. For inverse functions, a common line of reflection is \( y = x \). If a function and its inverse are plotted, ideally, they should appear as mirror images relative to this line.In our example, we have:
- The original function \( f(x) = 2 - e^x \).
- Its inverse \( f^{-1}(x) = \ln(2 - x) \).
- The line \( y = x \) which serves as the mirror line for reflection.
- Select a point on the function's graph. For \( f(x) = 2 - e^x \), this could be the point \((0, 1)\).
- Locate where this point reflects on the inverse graph \( f^{-1}(x) = \ln(2 - x) \). You should find that if \((a, b)\) is on \( f \), then \((b, a)\) is on \( f^{-1} \).
- If both points are indeed symmetrical about the line \( y = x \), reflection is confirmed.
Natural Logarithm
The natural logarithm, denoted by \( \ln(x) \), is the inverse operation of exponentiation with base \( e \). While an exponential function raises \( e \) to a power, the natural logarithm finds which power an exponential function was raised to get a certain number.Consider the relation in finding the inverse:
- We begin with \( e^x = 2 - y \).
- Using \( \ln \) on both sides \( x = \ln(2 - y) \), reveals how \( x \) is derived from the exponential term \( 2 - y \).
- \( \ln(1) = 0 \).
- \( \ln(e) = 1 \). The natural log "undoes" the exponent \( e \), reinforcing its role as an inverse.
- It increases logarithmically (slowly at first), as input values increase from a positive number.