Chapter 5: Problem 50
In Exercises 47–52, solve the nonlinear system. Justify your answer with a graph. $$ \begin{aligned} &x^2+y^2=25 \\ &y=-\frac{3}{4} x+\frac{25}{4} \end{aligned} $$
Short Answer
Expert verified
The solution to the system of equations are two points: (-3, 4) and (4, -3).
Step by step solution
01
Substitute the second equation into the first one
Replace \( y \) in the first equation \( x^2 + y^2 = 25 \) with the second equation \( y = -\frac{3}{4}x + \frac{25}{4} \). This gives \( x^2 + (-\frac{3}{4}x + \frac{25}{4})^2 = 25. \)
02
Solve for x
First expand the terms and simplify the equation to a quadratic equation. Then solve for \( x \). This should give two solutions for \( x \). To solve for these values use the quadratic formula \( x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a} \).
03
Solve for y
Substitute each solution for \( x \) into the second equation to get corresponding \( y \) values. This should give two corresponding \( y \) values.
04
Justify with a graph
Graph both original equations in the same coordinate plane. The points of intersection should match the solutions found.
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Quadratic Equation
A quadratic equation is a type of polynomial equation of the form \( ax^2 + bx + c = 0 \), where \( a, b, \) and \( c \) are constants, and \( a eq 0 \). In the given exercise, the equation \( x^2 + y^2 = 25 \) represents a circle, which is a form of a quadratic equation in two variables. In any system involving quadratic equations, solving these involves finding the values of \( x \) and \( y \) that satisfy the equation.
This equation can sometimes result in two solutions, no real solutions, or infinite solutions depending on the discriminant \( b^2 - 4ac \). A positive discriminant indicates two distinct solutions, zero means one solution, and a negative discriminant indicates no real solution.
When solving, you might use the quadratic formula: \[ x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a} \] to find these values.
This equation can sometimes result in two solutions, no real solutions, or infinite solutions depending on the discriminant \( b^2 - 4ac \). A positive discriminant indicates two distinct solutions, zero means one solution, and a negative discriminant indicates no real solution.
When solving, you might use the quadratic formula: \[ x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a} \] to find these values.
System of Equations
A system of equations involves solving two or more equations simultaneously to find common solutions. In this exercise, you have a nonlinear system because it includes a quadratic equation \( x^2 + y^2 = 25 \) and a linear equation \( y = -\frac{3}{4}x + \frac{25}{4} \).
To solve a system of equations, you aim to find the values of variables that satisfy all given equations at the same time. Nonlinear systems can have a finite number of solutions, like two points of intersection, or other complex numbers of solutions.
To solve a system of equations, you aim to find the values of variables that satisfy all given equations at the same time. Nonlinear systems can have a finite number of solutions, like two points of intersection, or other complex numbers of solutions.
- The process often involves using algebraic methods like substitution or elimination.
- In this exercise, substitution is employed to solve for the common points of intersection between the curve (circle) and the line.
Graphing Solutions
Graphing is a visual way to solve or confirm solutions to a system of equations. For the given equations \( x^2 + y^2 = 25 \) and \( y = -\frac{3}{4}x + \frac{25}{4} \), graphing helps to visually demonstrate the points of intersection. It is these intersection points that are the solution to the system.
Typically, you will:
Typically, you will:
- Plot each equation on the same graph.
- Observe where the graphs intersect since those points are solutions to the system.
- Confirm algebraic solutions graphically by checking if they correspond to intersection points.
Substitution Method
The substitution method is a powerful technique for solving systems of equations. It involves solving one equation for a single variable and substituting this solution into the other equations. In this exercise, \( y = -\frac{3}{4}x + \frac{25}{4} \) is substituted into \( x^2 + y^2 = 25 \).
This substitution leads to a single equation in one variable \( x \), which can then be solved using techniques like factoring or using the quadratic formula.
After finding the value(s) of \( x \), plug these back into the linear equation to find the corresponding \( y \) values. The substitution method simplifies complex systems by reducing the number of variables in the initial equations, making them more manageable.
This substitution leads to a single equation in one variable \( x \), which can then be solved using techniques like factoring or using the quadratic formula.
After finding the value(s) of \( x \), plug these back into the linear equation to find the corresponding \( y \) values. The substitution method simplifies complex systems by reducing the number of variables in the initial equations, making them more manageable.