Chapter 5: Problem 50
\(f(x)=\sqrt[3]{x^2+10 x}, g(x)=\frac{1}{4} f(-x)+6\)
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Chapter 5: Problem 50
\(f(x)=\sqrt[3]{x^2+10 x}, g(x)=\frac{1}{4} f(-x)+6\)
These are the key concepts you need to understand to accurately answer the question.
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MODELING WITH MATHEMATICS The period of a pendulum is the time the pendulum takes to complete one back-and-forth swing. The period \(T\) (in seconds) can be modeled by the function \(T=1.11 \sqrt{\ell}\), where \(\ell\) is the length (in feet) of the pendulum. Graph the function. Estimate the length of a pendulum with a period of 2 seconds. Explain your reasoning.
Your friend claims that every function has an inverse. Is your friend correct? Explain your reasoning.
Simplify the expression. Write your answer using only positive exponents. $$ 2^3 \cdot 2^2 $$
\(-8 y^2+2=x\)
In Exercises 35–46, determine whether the inverse of \(f\) is a function. Then find the inverse. $$ f(x)=\sqrt{x+4} $$
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