91Ó°ÊÓ

\(\sqrt[5]{32}\)

The windchill factor is a measure of the cooling effect that the wind has on a person's skin. It calculates the equivalent cooling temperature if there were no wind. The National Weather Service uses the formula $$ \text { Windchill temperature }=35.74+0.6215 T-35.75 V^{4 / 25}+0.4275 T V^{4 / 25} $$ where T is the temperature in \(^{\circ} \mathrm{F}\) and \(\mathrm{Vi}\) is the wind speed in miles per hour, to calculate wind- chill. The table gives the windchill factor for various wind speeds and temperatures at which frostbite is a risk, and how quickly it may occur. Use the formula to determine the windchill temperature to the nearest tenth of a degree, given the following conditions. Compare answers with the appropriate entries in the table. \(30^{\circ} \mathrm{F}, 15\) -mph wind

\(\sqrt[5]{-1024}\)

The windchill factor is a measure of the cooling effect that the wind has on a person's skin. It calculates the equivalent cooling temperature if there were no wind. The National Weather Service uses the formula $$ \text { Windchill temperature }=35.74+0.6215 T-35.75 V^{4 / 25}+0.4275 T V^{4 / 25} $$ where T is the temperature in \(^{\circ} \mathrm{F}\) and \(\mathrm{Vi}\) is the wind speed in miles per hour, to calculate wind- chill. The table gives the windchill factor for various wind speeds and temperatures at which frostbite is a risk, and how quickly it may occur. Use the formula to determine the windchill temperature to the nearest tenth of a degree, given the following conditions. Compare answers with the appropriate entries in the table. \(20^{\circ} \mathrm{F}, 20-\mathrm{mph}\) wind

The windchill factor is a measure of the cooling effect that the wind has on a person's skin. It calculates the equivalent cooling temperature if there were no wind. The National Weather Service uses the formula $$ \text { Windchill temperature }=35.74+0.6215 T-35.75 V^{4 / 25}+0.4275 T V^{4 / 25} $$ where T is the temperature in \(^{\circ} \mathrm{F}\) and \(\mathrm{Vi}\) is the wind speed in miles per hour, to calculate wind- chill. The table gives the windchill factor for various wind speeds and temperatures at which frostbite is a risk, and how quickly it may occur. Use the formula to determine the windchill temperature to the nearest tenth of a degree, given the following conditions. Compare answers with the appropriate entries in the table. \(40^{\circ} \mathrm{F}, 10\) -mph wind

\(-\sqrt[3]{x^{3}}\)

When approximating \(\sqrt{40}\) to three decimal places, a student incorrectly rounded \(\sqrt{40} \approx 6.32455532\) to \(6.324 .\) WHAT WENT WRONG? Give the correct approximation.

Find the equation of a circle satisfying the given conditions. Center: (-8,-5)\(;\) radius: \(\sqrt{5}\)

\(-\sqrt{91}\)

\(\sqrt[4]{250}\)