Chapter 6: Problem 61
Set up appropriate equations and solve the given stated problems. All numbers are accurate to at least two significant digits. A jet takes the same time to travel \(2580 \mathrm{km}\) with the wind as it does to travel \(1800 \mathrm{km}\) against the wind. If its speed relative to the air is \(450 \mathrm{km} / \mathrm{h},\) what is the speed of the wind?
Short Answer
Step by step solution
Understanding the problem
Formulating the equations
Cross-multiplying to eliminate the fractions
Expanding both sides
Simplifying the equation
Solving for w
Conclusion
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Equations
Speed and Distance
- Speed = Distance / Time
Word Problems
- Identify what you know (given data).
- Identify what you need to find (the unknowns).
- Understand the relationship between these quantities.
Cross-Multiplication
- You set up your equation from the two fractions \( \frac{2580}{450 + w} = \frac{1800}{450 - w} \)
- Then, cross-multiply: Multiply the numerator of one fraction by the denominator of the other and vice versa: \[ 2580 \times (450 - w) = 1800 \times (450 + w) \]