Chapter 6: Problem 65
Perform the indicated operations. Each expression occurs in the indicated area of application. $$\left(\frac{3 P x}{2 L^{2}}\right)^{2}+\left(\frac{P}{2 L}\right)^{2} \text { (force of a weld) }$$
Short Answer
Expert verified
\( \frac{9P^2x^2 + P^2L^2}{4L^4} \)
Step by step solution
01
Understanding the Given Expression
The given expression is \( \left(\frac{3Px}{2L^{2}}\right)^{2} + \left(\frac{P}{2L}\right)^{2} \). It represents the total force of a weld in terms of the variables \( P \), \( x \), and \( L \). Our goal is to perform the indicated operations and simplify this expression.
02
Squaring the First Term
Focus on the first term \( \left(\frac{3Px}{2L^2}\right)^2 \). To square a fraction, square the numerator and the denominator separately: \( \left(\frac{3Px}{2L^2}\right)^2 = \frac{(3Px)^2}{(2L^2)^2} = \frac{9P^2x^2}{4L^4} \). This is the result of squaring the first fraction.
03
Squaring the Second Term
Now square the second term \( \left(\frac{P}{2L}\right)^2 \). Similarly, square both the numerator and the denominator: \( \left(\frac{P}{2L}\right)^2 = \frac{P^2}{4L^2} \). This completes the squaring of the second fraction.
04
Adding the Results
Combine the results from Step 2 and Step 3 by adding them together:\[\frac{9P^2x^2}{4L^4} + \frac{P^2}{4L^2}\]To add these fractions, we must first have a common denominator, which will be \( 4L^4 \).
05
Adjusting the Denominator of Second Term
Adjust the second fraction to have the common denominator \( 4L^4 \). This means we rewrite \( \frac{P^2}{4L^2} \) as \( \frac{P^2L^2}{4L^4} \). Now, both fractions have the same denominator.
06
Combining the Two Fractions
With both fractions having the common denominator \( 4L^4 \), we can add them:\[\frac{9P^2x^2}{4L^4} + \frac{P^2L^2}{4L^4} = \frac{9P^2x^2 + P^2L^2}{4L^4}\].This provides the simplified expression of the weld force.
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Squaring Fractions
Squaring a fraction is a straightforward process. You need to square both the numerator and the denominator separately. For example, if you have the fraction \( \frac{a}{b} \), its square would be \( \left(\frac{a}{b}\right)^2 = \frac{a^2}{b^2} \).
This operation can be remembered as:
This results in \( \frac{9P^2x^2}{4L^4} \). Remember that squaring each element individually is key to simplifying such expressions correctly.
This operation can be remembered as:
- Square the top number (numerator).
- Square the bottom number (denominator).
- Write the new fraction with the squared results.
This results in \( \frac{9P^2x^2}{4L^4} \). Remember that squaring each element individually is key to simplifying such expressions correctly.
Addition of Fractions
Adding fractions requires a common denominator. Without a common denominator, the fractions can't be directly added. When faced with fractions such as \( \frac{a}{b} + \frac{c}{d} \), find a number that both denominators can divide into, called the least common denominator (LCD).
To add:
Now, both fractions can be added, resulting in \( \frac{9P^2x^2 + P^2L^2}{4L^4} \). The rule of matching denominators helps combine fractions smoothly in many algebraic operations.
To add:
- Rewrite each fraction with the LCD as the new denominator.
- Adjust the numerators accordingly by multiplying by the appropriate factor used in creating the new denominators.
- Add the adjusted numerators, keeping the common denominator the same.
Now, both fractions can be added, resulting in \( \frac{9P^2x^2 + P^2L^2}{4L^4} \). The rule of matching denominators helps combine fractions smoothly in many algebraic operations.
Weld Force Calculation
In engineering, especially when dealing with structures, calculating the force on a weld is crucial. The given expression combines different forces into a single value. Considering variables \( P \), \( x \), and \( L \), you can determine the force acting on a weld by simplifying the provided mathematical expression.
Let's break down its components:
Let's break down its components:
- \( P \) - Represents a load or pressure applied.
- \( x \) - Often represents a distance or a particular dimension of the structure.
- \( L \) - Often a reference length or another dimension related to the structure's layout.