Chapter 13: Problem 8
Find the common logarithm of each of the given numbers by using a calculator. $$8.043 \times 10^{-8}$$
Short Answer
Expert verified
The common logarithm of \( 8.043 \times 10^{-8} \) is approximately \(-7.0944\).
Step by step solution
01
Understand Common Logarithm
A common logarithm is the logarithm with base 10. We denote it as \( \log_{10} \) or simply \( \log \).
02
Express the Number in Standard Form
The given number is already in scientific notation: \( 8.043 \times 10^{-8} \). In this notation, \( 8.043 \) is the coefficient and \( 10^{-8} \) represents the power of ten.
03
Break Down the Logarithm Calculation
Utilize the logarithm properties: \( \log(a \times b) = \log(a) + \log(b) \). Hence, \( \log(8.043 \times 10^{-8}) = \log(8.043) + \log(10^{-8}) \).
04
Calculate the First Logarithm
Use a calculator to find \( \log(8.043) \). Inputting 8.043 into a calculator yields \( \log(8.043) \approx 0.9056 \).
05
Calculate the Power of Ten Logarithm
Recall \( \log(10^{n}) = n \) for any integer \( n \). Hence, \( \log(10^{-8}) = -8 \).
06
Combine the Results
Now, add the results together: \( \log(8.043 \times 10^{-8}) = 0.9056 + (-8) \). Perform the addition to get \( \log(8.043 \times 10^{-8}) \approx -7.0944 \).
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Scientific Notation
Scientific notation is a method used to write very large or very small numbers in a concise form. It expresses numbers as a product of two parts: a coefficient and a power of ten. This makes it easier to read and manage numbers, especially in fields like science and engineering.
For example, the number \(8.043 \times 10^{-8}\) consists of two parts: the coefficient \(8.043\) and the power of ten, \(10^{-8}\). The coefficient should be a number greater than or equal to 1 but less than 10. The power of ten indicates how many times you multiply the coefficient by ten. If the exponent is negative, like \(-8\) in this case, it means the coefficient is divided by ten multiple times. This helps to represent decimal numbers accurately.
For example, the number \(8.043 \times 10^{-8}\) consists of two parts: the coefficient \(8.043\) and the power of ten, \(10^{-8}\). The coefficient should be a number greater than or equal to 1 but less than 10. The power of ten indicates how many times you multiply the coefficient by ten. If the exponent is negative, like \(-8\) in this case, it means the coefficient is divided by ten multiple times. This helps to represent decimal numbers accurately.
- Example 1: \(123,000 = 1.23 \times 10^5\)
- Example 2: \(0.000076 = 7.6 \times 10^{-5}\)
Logarithm Properties
Logarithms are a way to understand the inverse of exponential growth. Common logarithms have a base of 10, often represented as \(\log\) without a subscript. They are crucial in simplifying multiplication into addition using their properties.
Here are some key properties:
Here are some key properties:
- Product Rule: \(\log(a \times b) = \log(a) + \log(b)\). This property breaks down multiplication within a logarithm into the addition of two separate logs. It was used in the exercise to separate \(\log(8.043 \times 10^{-8})\) into \(\log(8.043) + \log(10^{-8})\).
- Power Rule: \(\log(a^n) = n \times \log(a)\). This helps when dealing with logarithms of powers.
- Quotient Rule: \(\log(\frac{a}{b}) = \log(a) - \log(b)\). This property simplifies division into subtraction within logarithms.
Calculation Using Calculator
When finding logarithms, a calculator can make the process quick and accurate. Most scientific calculators have a dedicated button for calculating common logarithms, usually labeled as "log". To find the logarithm of a number using a calculator, follow these steps:
- Step 1: Enter the number for which you want to find the logarithm. For instance, type \(8.043\).
- Step 2: Press the "log" button. The calculator will immediately provide the result, which in this case is \(\log(8.043) \approx 0.9056\).
- Step 3: For powers of ten, remember that \(\log(10^n) = n\). So for \(10^{-8}\), the calculation is straightforward: \(-8\).