Chapter 13: Problem 32
$$\text {Plot the indicated graphs.}$$ In undergoing an adiabatic (no heat gained or lost) expansion of a gas, the relation between the pressure \(p\) (in \(\mathrm{kPa}\) ) and the volume \(v\) (in \(\mathrm{m}^{3}\) ) is \(p^{2} v^{3}=850 .\) On log-log paper, graph \(p\) as a function of \(v\) from \(v=0.10 \mathrm{m}^{3}\) to \(v=10 \mathrm{m}^{3}\)
Short Answer
Step by step solution
Understand the Relationship
Solve for Pressure
Transform to Logarithmic Form
Prepare the Equation for Graphing
Plot Key Points
Draw the Graph
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Logarithmic Function
- This transformation converts the multiplicative relationship into an additive one, which is much easier to plot on a linear scale.
- It allows for the examination of exponential and power relationships by visualizing them as straight lines.
- The slope and intercept in the log-transformed equation give insights into the behavior of the original data set.
Graphing Techniques
- The negative slope, \(-\frac{3}{2}\), indicates that as volume increases, pressure decreases in a systematic manner.
- The y-intercept, \(\frac{1}{2}\log(850)\), offers a starting point on the graph that aligns with known data points, ensuring accuracy.
- This approach mitigates the distortions that can occur when plotting exponential growth or decline on a standard graph.
Mathematical Modeling
- Mathematical modeling helps highlight key variables and their interactions, providing a clear picture of the underlying physical processes.
- Modeling enables predictions and simulations of behavior using derived equations, facilitating the exploration of "what-if" scenarios.
- The log transformation unveils the linear characteristics of exponential-growth models, ensuring they can be plotted easily and analyzed thoroughly.