/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 24 Find the natural antilogarithms ... [FREE SOLUTION] | 91Ó°ÊÓ

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Find the natural antilogarithms of the given logarithms. $$5.420$$

Short Answer

Expert verified
The natural antilogarithm of 5.420 is approximately 225.545.

Step by step solution

01

Understand the Concept of Antilogarithms

Antilogarithms are the inverse functions of logarithms. The natural antilogarithm is specifically the inverse of the natural logarithm (ln), which uses the base \(e\), where \(e\) is approximately 2.718.
02

Set Up the Exponential Equation

To find the antilogarithm of 5.420, we must solve the equation \(x = e^{5.420}\), where \(e\) is the base of the natural logarithm.
03

Calculate the Exponentiation

Using a calculator, compute \(e^{5.420}\). Ensure your calculator is set to the correct mode (typically 'EXP' or 'e^x' mode), then input the value to get the result.
04

Interpret the Result

After calculating \(e^{5.420}\) using a calculator, we find the approximate value. This result is the natural antilogarithm of 5.420.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Inverse Functions
An inverse function essentially reverses the process of another function. Imagine you have a pair of operations that undo each other. That's how inverse functions work. For every function, there can be an inverse that "undoes" it. It's like pressing an "undo" button in math. For example, the inverse function of addition with 5 is subtraction by 5. The key relationship is the idea of undoing a process or operation.

Inverse functions are critical in mathematics as they allow us to reverse operations to solve for unknowns. In the context of logarithms, the inverse of a logarithm is an exponential function. Specifically, an antilogarithm reverses the process of a logarithmic operation.
  • Logarithm undoes exponentiation.
  • Antilogarithm (inverse of logarithm) undoes the logarithm, similar to how subtracting is the inverse of adding.
Natural Logarithm
A natural logarithm is a specific type of logarithm that uses the mathematical constant \(e\) as its base. The constant \(e\) is approximately equal to 2.718 and is known for its unique properties in calculus and natural growth processes. The notation for the natural logarithm is \(\ln(x)\).

The natural logarithm has several interesting characteristics:
  • \(\ln(e) = 1\) since \(e^1 = e\).
  • \(\ln(1) = 0\) because any number raised to the power of 0 is 1, including \(e\).
Natural logarithms are widely used in scientific fields because they simplify the mathematics of exponential growth and decay processes. For example, they help model population growth or radioactive decay. They transform multiplication operations into addition, making complex equations easier to solve.
Exponential Equation
An exponential equation involves variables located in the exponent of an expression. Understanding exponential equations is crucial when dealing with antilogarithms. In our original problem, calculating the natural antilogarithm of a given logarithm required setting up an exponential equation.

The standard form of an exponential equation is \(x = e^y\), where "\(x\)" is the result, "\(e\)" is the base, and "\(y\)" is the exponent. In the context of finding natural antilogarithms:
  • You convert the logarithmic expression into an exponential form.
  • The solution involves calculating \(e^y\), effectively reversing the logarithm operation to find \(x\).
In our example, to find the natural antilogarithm of 5.420, we express it as an exponential equation: \(x = e^{5.420}\). This process involves using a calculator to compute the value of \(e^{5.420}\) to determine the natural antilogarithm, showcasing an application of exponentials in solving real-world mathematical problems.

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Most popular questions from this chapter

$$\text {Plot the indicated graphs.}$$ In undergoing an adiabatic (no heat gained or lost) expansion of a gas, the relation between the pressure \(p\) (in \(\mathrm{kPa}\) ) and the volume \(v\) (in \(\mathrm{m}^{3}\) ) is \(p^{2} v^{3}=850 .\) On log-log paper, graph \(p\) as a function of \(v\) from \(v=0.10 \mathrm{m}^{3}\) to \(v=10 \mathrm{m}^{3}\)

World population is currently growing by \(1.1 \%\) annually. If it continues at this rate, the time (in years) for the population to double in size is given by \(t=\frac{\ln 2}{\ln 1.011} .\) How many years is this (to the nearest year)?

Perform the indicated operations. In Exercise \(47,\) the graph of \(y=\log _{0.5} x\) is plotted. By inspecting the graph and noting the properties of \(\log _{0.5} x,\) describe some of the differences of logarithms to a base less than 1 from those to a base greater than 1.

$$\text {Plot the indicated graphs.}$$ The atmospheric pressure \(p\) (in kPa) at a given altitude \(h\) (in \(\mathrm{km}\) ) is given in the following table. On semilog paper, plot \(p\) as a function of \(h\) $$\begin{array}{l|c|c|c|c|c} h(\mathrm{km}) & 0 & 10 & 20 & 30 & 40 \\ \hline p(\mathrm{kPa}) & 101 & 25 & 6.3 & 2.0 & 0.53 \end{array}$$

Use a calculator to solve the given equations. The atmospheric pressure \(P\) (in bars) at an altitude \(h\) (in \(\mathrm{km}\) ) above Earth's surface can be estimated using the equation \(P=e^{-h / 7} .\) Solve for \(h\) as a function of \(P .\) At what elevation is the pressure 0.35 bars?

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