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At the downtown office of First National Bank, there are five tellers. Last week, the tellers made the following number of errors each: \(2,3,5,3,\) and \(5 .\) a. How many different samples of two tellers are possible? b. List all possible samples of size 2 and compute the mean of each. c. Compute the mean of the sample means and compare it to the population mean.

Short Answer

Expert verified
There are 10 samples; the mean of sample means is 3.6, matching the population mean.

Step by step solution

01

Calculate Total Samples

To find how many different samples of two tellers are possible, we use the combination formula. The formula for combinations is \( \binom{n}{r} \), where \( n \) is the total number of items to choose from, and \( r \) is the number of items to choose. Here, we have \( n = 5 \) and \( r = 2 \), so the number of combinations is \( \binom{5}{2} = \frac{5!}{2!(5-2)!} = 10 \). There are 10 possible samples.
02

List Possible Samples

The possible samples of size 2 are: 1. (2, 3) 2. (2, 5) 3. (2, 3) 4. (2, 5) 5. (3, 5) 6. (3, 3) 7. (3, 5) 8. (5, 5) 9. (3, 5) 10. (3, 5)
03

Compute Mean of Each Sample

Compute the mean of each sample:1. (2, 3): Mean = \((2+3)/2 = 2.5\)2. (2, 5): Mean = \((2+5)/2 = 3.5\)3. (2, 3): Mean = \((2+3)/2 = 2.5\)4. (2, 5): Mean = \((2+5)/2 = 3.5\)5. (3, 5): Mean = \((3+5)/2 = 4.0\)6. (3, 3): Mean = \((3+3)/2 = 3.0\)7. (3, 5): Mean = \((3+5)/2 = 4.0\)8. (5, 5): Mean = \((5+5)/2 = 5.0\)9. (3, 5): Mean = \((3+5)/2 = 4.0\)10. (3, 5): Mean = \((3+5)/2 = 4.0\)
04

Calculate Mean of Sample Means

Calculate the mean of the sample means obtained from Step 3. The sample means are 2.5, 3.5, 2.5, 3.5, 4.0, 3.0, 4.0, 5.0, 4.0, 4.0.Thus, Mean of Sample Means = \(\frac{2.5 + 3.5 + 2.5 + 3.5 + 4.0 + 3.0 + 4.0 + 5.0 + 4.0 + 4.0}{10} = \frac{36}{10} = 3.6\).
05

Calculate Population Mean

To calculate the population mean, sum all the tellers' errors then divide by the number of tellers: Population mean = \(\frac{2+3+5+3+5}{5} = \frac{18}{5} = 3.6\).
06

Compare Means

Compare the mean of the sample means from Step 4 (3.6) to the population mean from Step 5 (3.6). They are equal, as expected in statistical sampling with replacement.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Combination Formula
The combination formula is a mathematical way to find out how many different groups can be formed from a larger set. When you want to choose a group of items but the order doesn't matter, you use combinations. This is different from permutations, where the order does matter.

To calculate combinations, we use the formula \( \binom{n}{r} = \frac{n!}{r!(n-r)!} \), where:
  • \( n \) is the total number of items.
  • \( r \) is the number of items you want to choose.
  • The exclamation mark \(!\) represents a factorial, which means multiplying the number by all the positive integers below it.
Let’s consider the exercise: You have 5 tellers and you want to sample 2 of them. Plugging these values into the formula gives us \( \binom{5}{2} = \frac{5!}{2!(5-2)!} = 10 \). This means there are 10 possible ways to choose 2 tellers from a group of 5.
Sample Means
Sample means are calculated by averaging the samples you take from a larger population. In statistics, it's crucial because it gives a point of reference about the population based on smaller, manageable subsets.

For instance, in the exercise, we have several samples of 2 tellers and for each pair, we calculate the average number of errors they made. This results in a list of sample means:
  • (2, 3): Mean = \((2+3)/2 = 2.5\)
  • (2, 5): Mean = \((2+5)/2 = 3.5\)
  • (3, 5): Mean = \((3+5)/2 = 4.0\)
  • and so on...
Each mean gives a mini snapshot of the population, helping us get a clearer understanding of the data’s range and tendencies, without analyzing every single data point.
Population Mean
The population mean is the average of all data points in an entire population. This is important because it provides a complete picture of the data as opposed to the sample mean, which only focuses on portions of it.

To find the population mean, you add up all the data points and divide by the total number of points. For the exercise, this is done by summing the tellers' errors: \(2 + 3 + 5 + 3 + 5 = 18\). You then divide this sum by the number of tellers, which is 5. So, the population mean is \(\frac{18}{5} = 3.6\).

Having the population mean allows us to verify if our sample means are accurately reflecting the larger dataset. In this exercise, both the population mean and the mean of the sample means were 3.6, showing accurate sampling.
Sampling with Replacement
Sampling with replacement means that after choosing an item from the population, it is returned before the next selection. This ensures each sample selection is independent and maintains the population size across different sample selections.

In the context of the exercise, each time you pick two tellers and calculate the mean errors, the tellers go back into the pool for the next sample selection. This keeps the sampling process fair and consistent with how probability works.

Sampling with replacement allows statisticians to gather numerous samples and calculate accurate statistics, which increases the reliability of results when sampling a population. It can sometimes lead to repeated data points in samples, but it also reflects the randomness and variability realistically encountered in larger populations.

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Most popular questions from this chapter

In a certain section of Southern California, the distribution of monthly rent for a one-bedroom apartment has a mean of \(\$ 2,200\) and a standard deviation of \(\$ 250 .\) The distribution of the monthly rent does not follow the normal distribution. In fact, it is positively skewed. What is the probability of selecting a sample of 50 one-bedroom apartments and finding the mean to be at least \(\$ 1,950\) per month?

A normal population has a mean of 75 and a standard deviation of 5 . You select a sample of \(40 .\) Compute the probability the sample mean is: a. Less than 74 . b. Between 74 and 76 . c. Between 76 and 77 . d. Greater than 77 .

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A population consists of the following three values: \(1,2,\) and \(3 .\) a. Sampling with replacement, list all possible samples of size 2 and compute the mean of every sample. b. Find the means of the distribution of the sample mean and the population mean. Compare the two values. c. Compare the dispersion of the population with that of the sample mean. d. Describe the shapes of the two distributions.

A population consists of the following five values: \(12,12,14,15,\) and \(20 .\) a. List all samples of size \(3,\) and compute the mean of each sample. b. Compute the mean of the distribution of sample means and the population mean. Compare the two values. c. Compare the dispersion in the population with that of the sample means.

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