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The distribution of the number of viewers for the American Idol television show follows a normal distribution with a mean of 29 million and a standard deviation of 5 million. What is the probability next week's show will: a. Have between 30 and 34 million viewers? b. Have at least 23 million viewers? c. Exceed 40 million viewers?

Short Answer

Expert verified
a. 26.2% probability, b. 88.5% probability, c. 1.39% probability.

Step by step solution

01

Understanding the Normal Distribution

The given problem follows a normal distribution with a mean (\( \mu \)) of 29 million and a standard deviation (\( \sigma \)) of 5 million. We will use these values to find probabilities regarding number of viewers.
02

Standardizing the Variable

To work with the normal distribution, we first convert viewer values to z-scores. The z-score formula is: \[ z = \frac{X - \mu}{\sigma} \] where \(X\) is the value in the distribution.
03

Calculating the Probability for Part (a)

For 30 million viewers, the z-score is \( z = \frac{30 - 29}{5} = 0.2 \). For 34 million viewers, the z-score is \( z = \frac{34 - 29}{5} = 1.0 \). Use a standard normal distribution table or calculator to find \( P(0.2 < Z < 1.0) \). The cumulative probability for \( Z = 1.0 \) is 0.8413, and for \( Z = 0.2 \) is 0.5793. Thus, the probability is \( 0.8413 - 0.5793 = 0.262 \).
04

Calculating the Probability for Part (b)

For 23 million viewers, the z-score is \( z = \frac{23 - 29}{5} = -1.2 \). Use a standard normal distribution table or calculator to find \( P(Z > -1.2) \). The cumulative probability for \( Z = -1.2 \) is 0.1151. Therefore, the probability is \( 1 - 0.1151 = 0.8849 \).
05

Calculating the Probability for Part (c)

For 40 million viewers, the z-score is \( z = \frac{40 - 29}{5} = 2.2 \). Use a standard normal distribution table or calculator to find \( P(Z > 2.2) \). The cumulative probability for \( Z = 2.2 \) is 0.9861. Thus, the probability is \( 1 - 0.9861 = 0.0139 \).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Z-score calculation
The z-score is a statistical measurement that describes a value's relation to the mean of a group of values. It tells us how many standard deviations the value is from the mean. In this context, it helps us assess where a particular viewer count falls within the normal distribution of viewers.To calculate the z-score, we use the formula:
  • \[ z = \frac{X - \mu}{\sigma} \]
Here, \(X\) is the data point (viewer count), \(\mu\) is the mean, and \(\sigma\) is the standard deviation.For example, if you want to find the z-score for 30 million viewers, and the mean is 29 million with a standard deviation of 5 million, you plug these values into the formula:
  • \( z = \frac{30 - 29}{5} = 0.2 \)
This process allows us to use standardized values to find probabilities, making it easier to work with the normal distribution tables or calculators.
Probability
Probability quantifies the chance of an event occurring. It ranges from 0 to 1. A probability of 0 means the event will not occur, while a probability of 1 means the event is certain to occur. Understanding probability is crucial to determining the likelihood of different viewership scenarios for American Idol. When calculating probabilities of certain events, such as having between 30 and 34 million viewers, we use the z-scores derived from those viewer numbers. We look up these z-scores in a standard normal distribution table or use a calculator to find the probability associated with being between these values on the normal curve. A helpful way to understand this is to visualize a curve where each point corresponds to a probability of occurrence. Common probabilities we might calculate include:
  • The probability that viewership is less than a specific value.
  • The probability that viewership is between two values.
  • The probability that viewership is more than a certain value.
Using z-scores, we can easily determine these probabilities.
Cumulative probability
Cumulative probability is the probability that a random variable will have a value less than or equal to a given point. To find cumulative probability, you sum up probabilities following the curve up to that point.For instance, if you're asked to find the probability that a show has at least 23 million viewers, first find the cumulative probability of the z-score for 23 million. In our example, the z-score for 23 million viewers is -1.2.Then, using a z-score table or calculator, identify the probability associated with \(Z = -1.2\), which is 0.1151. This figure represents the probability of fewer than 23 million viewers. Therefore, the probability of at least 23 million viewers is:
  • \(1 - 0.1151 = 0.8849\)
This approach allows us to understand probabilities cumulatively, which means from the leftmost part of the distribution up to the specified point.
Standard normal distribution
The standard normal distribution is a special type of normal distribution. It has a mean of 0 and a standard deviation of 1. It is often depicted as a beautifully symmetric bell curve. This standardization allows us to easily determine probabilities by simplifying the comparison process of different normal distributions to a standard form. Once random variables are converted into z-scores, we use this standardized curve to find probabilities. For instance, if a z-score of a viewer count is given, it can be plotted on the standard normal distribution curve to easily find its cumulative probability using a table or calculator. The closer the z-score is to 0, the closer the probability is to 0.5, since 0 is the mean of the standard normal distribution. Why use the standard normal distribution?
  • It simplifies calculations by comparing different points on the same scale.
  • It helps estimate probabilities for any normal distribution once translated to a common ground.
  • Any normal distribution can be translated to a standard form using z-scores.
The symmetry and standardized format make it user-friendly for probability estimation.

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Most popular questions from this chapter

Explain what is meant by this statement: "There is not just one normal probability distribution but a 'family' of them."

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