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Compute the mean and variance of the following discrete probability distribution. $$ \begin{array}{|cc|} \hline x & P(x) \\ \hline 0 & .2 \\ 1 & .4 \\ 2 & .3 \\ 3 & .1 \\ \hline \end{array} $$

Short Answer

Expert verified
The mean is 1.3 and the variance is 0.81.

Step by step solution

01

Identify Values and Probabilities

Identify the random variable values and their corresponding probabilities from the table given: \[ x = \{0, 1, 2, 3\}, \ P(x) = \{0.2, 0.4, 0.3, 0.1\} \].
02

Compute the Mean (Expected Value)

Calculate the mean (expected value) of the distribution using the formula \( E(X) = \sum (x_i \cdot P(x_i)) \), where \( x_i \) are the values of the random variable and \( P(x_i) \) are their probabilities. \[ E(X) = (0 \cdot 0.2) + (1 \cdot 0.4) + (2 \cdot 0.3) + (3 \cdot 0.1) = 0 + 0.4 + 0.6 + 0.3 = 1.3 \].
03

Compute E(X^2)

Calculate \( E(X^2) \) which is needed for the variance. Use the formula \( E(X^2) = \sum (x_i^2 \cdot P(x_i)) \). \[ E(X^2) = (0^2 \cdot 0.2) + (1^2 \cdot 0.4) + (2^2 \cdot 0.3) + (3^2 \cdot 0.1) = 0 + 0.4 + 1.2 + 0.9 = 2.5 \].
04

Compute the Variance

Calculate the variance using the formula \( Var(X) = E(X^2) - [E(X)]^2 \). \[ Var(X) = 2.5 - (1.3)^2 = 2.5 - 1.69 = 0.81 \].

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Mean Calculation
To find the mean of a discrete probability distribution, you need to determine what is commonly referred to as the 'Expected Value' (E(X)). This is essentially a measure of the center of the distribution, providing a sense of the average outcome you can expect.

The formula for the mean in a probability distribution is:
  • \( E(X) = \sum (x_i \cdot P(x_i)) \)
Where:
  • \( x_i \) are the values of the random variable
  • \( P(x_i) \) are the probabilities associated with these values
To illustrate, using the provided data:
  • \( E(X) = (0 \cdot 0.2) + (1 \cdot 0.4) + (2 \cdot 0.3) + (3 \cdot 0.1) \)
  • This simplifies to \( 0 + 0.4 + 0.6 + 0.3 = 1.3 \)
Thus, the mean or expected value is 1.3, providing us a point of reference for what is typical in this distribution.
Variance Calculation
Variance is a crucial statistical measure that tells you how much the values in your distribution vary or spread out from the mean. It helps to understand the degree of uncertainty or risk associated with a random variable.

The variance \( Var(X) \) is calculated with this formula:
  • \( Var(X) = E(X^2) - [E(X)]^2 \)
Initially, we need to find \( E(X^2) \), which represents the expected value of the squares of the random variable. The calculation for \( E(X^2) \) uses:
  • \( E(X^2) = \sum (x_i^2 \cdot P(x_i)) \)
From the given example:
  • \( E(X^2) = (0^2 \cdot 0.2) + (1^2 \cdot 0.4) + (2^2 \cdot 0.3) + (3^2 \cdot 0.1) \)
  • This equals \( 0 + 0.4 + 1.2 + 0.9 = 2.5 \)
Now, we calculate variance as follows:
  • \( Var(X) = 2.5 - (1.3)^2 \)
  • Which results in \( 2.5 - 1.69 = 0.81 \)
Thus, the variance of this distribution is 0.81, indicating the average degree to which each value differs from the mean.
Expected Value
The expected value is a fundamental concept that gives an average of all possible outcomes in a probability distribution, weighted by their respective probabilities. It acts as a benchmark for making decisions in a probabilistic framework by predicting what happens on average over many trials.

In simpler terms, it tells you the expected result when an experiment is repeated many times. This makes it incredibly useful in real-life scenarios such as games of chance, insurance modeling, and various fields of risk management.

The steps to calculate the expected value, as outlined earlier, involve multiplying each possible outcome by its probability and summing the results. Here's a quick recap:
  • Identify each outcome \( x_i \) and its probability \( P(x_i) \).
  • Calculate \( E(X) = \sum (x_i \cdot P(x_i)) \).
By giving you insights into the likely average outcome, the expected value serves as a powerful tool to steer decisions and predictions.

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Most popular questions from this chapter

It is estimated that \(0.5 \%\) of the callers to the Customer Service department of Dell Inc. will receive a busy signal. What is the probability that of today's 1,200 callers, at least 5 received a busy signal?

For each of the following, indicate whether the random variable is discrete or continuous. a. The length of time to get a haircut. b. The number of cars a jogger passes each morning while running. c. The number of hits for a team in a high school girls' softball game. d. The number of patients treated at the South Strand Medical Center between 6 and 10 p.m. each night. e. The distance your car traveled on the last fill-up. f. The number of customers at the Oak Street Wendy's who used the drive- through facility. g. The distance between Gainesville, Florida, and all Florida cities with a population of at least 50,000 .

Automobiles arrive at the Elkhart exit of the Indiana Toll Road at the rate of two per minute. The distribution of arrivals approximates a Poisson distribution. a. What is the probability that no automobiles arrive in a particular minute? b. What is the probability that at least one automobile arrives during a particular minute?

Industry standards suggest that \(10 \%\) of new vehicles require warranty service within the first year. Jones Nissan in Sumter, South Carolina, sold 12 Nissans yesterday. a. What is the probability that none of these vehicles requires warranty service? b. What is the probability exactly one of these vehicles requires warranty service? c. Determine the probability that exactly two of these vehicles require warranty service. d. Compute the mean and standard deviation of this probability distribution.

Which of these variables are discrete and which are continuous random variables? a. The number of new accounts established by a salesperson in a year. b. The time between customer arrivals to a bank ATM. c. The number of customers in Big Nick's barber shop. d. The amount of fuel in your car's gas tank. e. The number of minorities on a jury. f. The outside temperature today.

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